传递成员函数作为参数/ c

b_object.for_each_x_do(function_f);

所以function_f将获得x成员的每个人并做任何事情.让我们说：

void function_f(x_member_type x){ cout << x << endl; }

好.所以我试图通过以下代码实现这一目标：

class b{
    int *x;
public:
    void foreach_x_do(void (*f)(int)){
            while(*x++)  // or any kind of iteration through x
                    f(*x);
    }
};

class a{
    b b_inst;
public:
    void f(int x) {  }     
    a(){
            b_inst.foreach_x_do(f); // by mistake it was b_inst.foreach_x_do(f)(),however this wasn't the point at all. 
    }
    ~a(){}
};

int main(){}

但是,我收到此错误,编译时：

fp.cpp: In constructor ‘a::a()’:
fp.cpp:17: error: no matching function for call to ‘b::foreach_x_do(<unresolved overloaded function type>)’
fp.cpp:6: note: candidates are: void b::foreach_x_do(void (*)(int))

任何人都可以帮助它编译？