如何在objective-c中处理json格式的嵌入式数组

发布时间：2020-12-16 07:17:22 所属栏目：百科来源：网络整理

导读：我有一个叫做数组的字典： { "encoding": "320","format": "MP3","media": "CD","name": "foo","remaster_title": "" },{ "encoding": "V0 (VBR)","name": "bar",{ "encoding": "Lossless","format": "FLAC","remaster_title": "hoho" } 我想将它们分开,以便

我有一个叫做数组的字典：

{
        "encoding": "320","format": "MP3","media": "CD","name": "foo","remaster_title": ""
    },{
        "encoding": "V0 (VBR)","name": "bar",{
        "encoding": "Lossless","format": "FLAC","remaster_title": "hoho"
    }

我想将它们分开,以便它们是独一无二的.例如,应该只有一个名称,因此将有两个部分：foo和bar.

然后在每个名称(foo或bar)内应该有remaster_title(对于foo：和bar都是：和hoho)….

这应该是顺序：name> remaster_title>媒体>格式>编码.

我认为如果我的格式类似于：

music[name][remaster_title][media][format] = encoding

那么所有的密钥会合并吗？

我试过了：

+(NSMutableDictionary*)handleReturnedArtistJson:(NSDictionary*)json{
    NSMutableDictionary *music = [[NSMutableDictionary alloc] init];
    for(NSDictionary *result in json[@"response"][@"group"]) {
        NSString* release_type = result[@"releaseType"];
        NSString* name = result[@"groupName"];

        if (![release_type  isEqual: @"Compilation"]){
            for (NSDictionary *subgroup in result[@"subgroup"]){
                NSString* media = subgroup[@"media"];
                NSString* remaster_title = subgroup[@"remasterTitle"];
                NSString* format = subgroup[@"format"];
                NSString* encoding = subgroup[@"encoding"];

                music[name][remaster_title][media][format] = encoding;
            }
        }
    }
    return music;
}

但NSLog(@“％@”,音乐);没有回报.

解决方法

评论区域太小,无法提出几个问题,但让我们假设一些事情.您想要将JSON解析为对象树.让我们看看这段代码是否有帮助.

#import <Foundation/Foundation.h>

typedef NSMutableDictionary<NSString*,NSString*> formatDictionary;
typedef NSMutableDictionary<NSString*,formatDictionary*> mediaDictionary;
typedef NSMutableDictionary<NSString*,mediaDictionary*> titleDictionary;
typedef NSMutableDictionary<NSString*,titleDictionary*> nameDictionary;

@interface DataSource : NSObject
- (nameDictionary*)parseJSONFile:(NSString *)jsonFile error:(NSError *__autoreleasing *)outError;
@end

履行

@implementation DataSource

- (NSString *)valueOrDefaultFromDictionary:(NSDictionary *) dictionary forKey: (NSString *) key
{
    NSString * value = dictionary[key];
    if (![value length]) {
        return @"";
    }
    return value;
}

- (NSArray *)jsonToArray:(NSString *)jsonFile error:(NSError *__autoreleasing *)outError
{
    NSString *path  = [[NSBundle mainBundle] pathForResource:jsonFile ofType:@"json"];
    NSString *jsonString = [[NSString alloc] initWithContentsOfFile:path encoding:NSUTF8StringEncoding error:nil];
    NSError *jsonError;
    NSArray *jsonDataArray = [NSArray new];
    jsonDataArray = [NSJSONSerialization JSONObjectWithData:[jsonString dataUsingEncoding:NSUTF8StringEncoding] options:kNilOptions error:&jsonError];

    if (jsonDataArray == nil) {
        if (outError) {
            *outError = [NSError errorWithDomain:@"yourdomain" code:-42 userInfo:@{NSUnderlyingErrorKey: jsonError}];
        }
        return nil;
    }
    return jsonDataArray;
}


- (nameDictionary*)parseJSONFile:(NSString *)jsonFile error:(NSError *__autoreleasing *)outError
{
    NSArray * jsonDataArray = [self jsonToArray:jsonFile error:outError];
    if (!jsonDataArray) {
      return nil;
    }
    nameDictionary* music = [nameDictionary new];

    [jsonDataArray enumerateObjectsUsingBlock:^(id _Nonnull obj,NSUInteger idx,BOOL * _Nonnull stop) {
        NSString * name = [self valueOrDefaultFromDictionary:obj forKey:@"name"];
        NSString * title = [self valueOrDefaultFromDictionary:obj forKey:@"remaster_title"];
        NSString * media = [self valueOrDefaultFromDictionary:obj forKey:@"media"];
        NSString * format = [self valueOrDefaultFromDictionary:obj forKey:@"format"];
        NSString * encoding = [self valueOrDefaultFromDictionary:obj forKey:@"encoding"];
        music[name] = [@{title: [@{media: [@{format:encoding} mutableCopy] } mutableCopy] } mutableCopy];
    }];
    return music;
}
@end

（编辑：李大同）

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