SWIG,C和Python:C临时对象过早删除
我有一个SWIG过早删除临时C对象的问题.
Python测试脚本的示例输出: -------------------------------------------------------------------------------- Works as expected: b0 = Buffer(0,) b1 = Buffer(1,1,) b0 = Buffer(0,) y = Buffer(0,) repr(b0) = Buffer(id = 0,vector at 0x020bf450,data at 0x020aeb30,size = 6) repr(y) = Buffer(id = 0,size = 6) Funny business: Deleting Buffer(id = 2) Deleting Buffer(id = 3) repr(b2) = Buffer(id = 2,vector at 0x020bf790,data at 0x00,size = 4257068) Deleting Buffer(id = 4) repr(b3) = Buffer(id = 4,vector at 0x02037040,data at 0x0204a4e0,size = 6) Deleting Buffer(id = 0) Deleting Buffer(id = 1) 删除缓冲区(id = X)是从Buffer :: ~Buffer()C代码中生成的,所以我们在这里可以看到,在Funny业务部分,C Buffer对象被过早删除了! Python对象b2和b3应该保持对id = 2和id = 4的C Buffer对象的引用. 我的所有代码都附在我的博客post上.但是,我将在这里总结一下代码: Buffer.hpp: #include <vector> #include <string> struct Buffer { Buffer(); Buffer(const Buffer & copy); ~Buffer(); Buffer & operator=(const Buffer & rhs); Buffer & operator<<(const Buffer & rhs); Buffer & operator<<(double rhs); std::string __str__() const; std::string __repr__() const; private: std::vector<double> _data; int _id; }; swig_test.i: %module swig_test %include "std_string.i" %{ #include "Buffer.hpp" #include <iostream> %} %ignore Buffer::operator=; %include "Buffer.hpp" go_test.py: from swig_test import Buffer def zeros(n): ''' Returns a Buffer filled with 'n' zeros. ''' b = Buffer() for i in xrange(n): b << 0.0 return b def ones(n): ''' Returns a Buffer filled with 'n' ones. ''' b = Buffer() for i in xrange(n): b << 1.0 return b def main(): #-------------------------------------------------------------------------- # This sections works as expected print "-" * 80 print "Works as expected:" b0 = zeros(3) print " b0 = ",b0 b1 = ones(3) print " b1 = ",b1 y = b0 << b1 print " b0 = ",b0 print " y = ",y print " b1 = ",b1 print " repr(b0) = ",repr(b0) print " repr(y) = ",repr(y) #-------------------------------------------------------------------------- # Funny things are happening here! print "Funny business:" b2 = zeros(3) << ones(3) print " repr(b2) = ",repr(b2) b3 = zeros(3) << 4.0 print " repr(b3) = ",repr(b3) if __name__ == "__main__": main() 我在博客文章中已经尝试了一些SWIG的东西,但我的SWIG-foo技能已经缩短了. 救救我社区,你是我唯一的希望! 更新1 我怀疑我有多个PyObjects将Buffer *保存到同一个C Buffer对象,所以当临时PyObject被垃圾收集时,它会删除C Buffer *. 所以,我想我需要一个Py_INCREF,但在哪里呢? 更新2 尝试按照jarod42的建议按值返回会破坏串联范例,例如: b = Buffer() b << 1 << 2 << 3 print b 只生产: Buffer(1,) 所以这不是我想要的. %newobject指令可用于释放函数或方法创建的新创建的对象(防止内存泄漏).在这种情况下,Buffer :: operator<<没有创建新对象. 解决方法
经过一番搜索后,我遇到了这个
thread,最终导致了一个有效的解决方案.
将typemap(out)与Py_INCREF结合使用就可以了. swig_test.i: %module swig_test %include "std_string.i" %{ #include "Buffer.hpp" #include <iostream> %} %ignore Buffer::operator=; %typemap(out) Buffer & operator<< { if(result) { /* suppress unused warning */ } Py_INCREF($self); $result = $self; } %include "Buffer.hpp" 现在我得到了我想要的行为(它与纯Python实现相匹配)并且没有内存泄漏. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |