c – 使用带有自定义对齐分配器实现的最新g编译SSE和-O3选项时的

它使用较旧的g版本使用相同的编译器标志编译并运行没有问题.当编译器标志“-mssse3 -O3”被删除或被更低的优化级别(例如“-O2”)替换时,它也会编译并运行没有问题.

如果同时使用旧的和新的g编译器,使编译器标记为“-msse2 -mssse3 -O3”并且具有可移植的对齐内存分配器是必需的,那么存在哪些选项？在下面的代码中是否有一个简单的错误可以轻松修复？最后,为什么存在这个错误？

使用gdb时,触发此错误的行是：“memory [i] =(unsigned char)i;”.

非常感谢提前.

#include <iostream>
using std::cerr;
using std::cout;
using std::endl;
using std::flush;
#include <stdlib.h>

void *aligned_alloc(int alignment,int size){
  const int pointer_size = sizeof(unsigned char *);
  const int requested_size = size + alignment - 1 + pointer_size;
  unsigned char *base = (unsigned char *)malloc(requested_size);
  if (base == NULL)  return NULL;
  unsigned char *start = base + pointer_size;
  const int trim_offset = (int)(((unsigned long long)(start+alignment-1)) & (alignment-1));
  unsigned char *aligned = start + alignment - 1 - trim_offset;
  *(unsigned char **)(aligned-pointer_size) = base;
  return aligned;
}
void aligned_free(void **aligned){
  if (*aligned == NULL)  return;
  unsigned char *base = *(unsigned char **)((unsigned char *)(*aligned) - sizeof(unsigned char *));
  free(base);
  *aligned = NULL;
}

int main(){
  unsigned char *memory = (unsigned char *)aligned_alloc(16,120);
  if (memory == NULL){
    cout<<"ERROR: Unable to allocate memory."<<endl;
    exit(1);
  }

  for (int i=0; i<120; i++){
    memory[i] = (unsigned char)i;
  }

  aligned_free((void **)&memory);

  return 0;
}