c – 如何跨核心同步TSC？

inline uint64_t rdtsc()
{
  uint32_t cycles_high;
  uint32_t cycles_low;

  asm volatile ("CPUIDnt"
      "RDTSCnt"
      "mov %%edx,%0nt"
      "mov %%eax,%1nt": "=r" (cycles_high),"=r" (cycles_low)::
      "%rax","%rbx","%rcx","%rdx");
  return ( ((uint64_t)cycles_high << 32) | cycles_low );
}

线程1正在运行

while(globalIndex < COUNT)
{
  while(globalIndex %2 == 0 && globalIndex < COUNT)
    ;
  cycles[globalIndex][0] = rdtsc();
  cycles[globalIndex][1] = cpuToBindTo;
  __sync_add_and_fetch(&globalIndex,1);
}

线程2正在运行

while(globalIndex < COUNT)
{
  while(globalIndex %2 == 1 && globalIndex < COUNT)
    ;
  cycles[globalIndex][0] = rdtsc();
  cycles[globalIndex][1] = cpuToBindTo;
  __sync_add_and_fetch(&globalIndex,1);
}

我看到了

CPU     rdtsc()         t1-t0
11 = 5023231563212740   990
03 = 5023231563213730   310
11 = 5023231563214040   990
03 = 5023231563215030   310
11 = 5023231563215340   990
03 = 5023231563216330   310
11 = 5023231563216640   990
03 = 5023231563217630   310
11 = 5023231563217940   990
03 = 5023231563218930   310
11 = 5023231563219240   990
03 = 5023231563220230   310
11 = 5023231563220540   990
03 = 5023231563221530   310
11 = 5023231563221840   990
03 = 5023231563222830   310
11 = 5023231563223140   990
03 = 5023231563224130   310
11 = 5023231563224440   990
03 = 5023231563225430   310
11 = 5023231563225740   990
03 = 5023231561739842   310
11 = 5023231561740152   990
03 = 5023231561741142   310
11 = 5023231561741452   12458
03 = 5023231561753910   458
11 = 5023231561754368   1154
03 = 5023231561755522   318
11 = 5023231561755840   982
03 = 5023231561756822   310
11 = 5023231561757132   990
03 = 5023231561758122   310
11 = 5023231561758432   990
03 = 5023231561759422   310

我不确定我是如何收到12458的乒乓球,但我想知道为什么我看到310-990-310而不是650-650-650.我认为tsc被认为是跨核心同步的.我的constant_tsc cpu标志已打开.