如何编写一个RestController来从XML请求更新JPA实体,Spring Data

id | first_name | last_name | date_of_birth 
----|------------|-----------|---------------
 1  | Tin        | Tin       | 2000-10-10

有一个名为Person的JPA实体映射到此表：

@Entity
@XmlRootElement(name = "person")
@XmlAccessorType(NONE)
public class Person {

    @Id
    @GeneratedValue
    private Long id;

    @XmlAttribute(name = "id")
    private Long externalId;

    @XmlAttribute(name = "first-name")
    private String firstName;

    @XmlAttribute(name = "last-name")
    private String lastName;

    @XmlAttribute(name = "dob")
    private String dateOfBirth;

    // setters and getters
}

该实体还使用JAXB注释进行注释,以允许XML有效负载
要映射到实体实例的HTTP请求.

我想实现一个端点来检索和更新具有给定id的实体.

根据this answer to a similar question,
我需要做的就是实现如下的处理程序方法：

@RestController
@RequestMapping(
        path = "/persons",consumes = APPLICATION_XML_VALUE,produces = APPLICATION_XML_VALUE
)
public class PersonController {

    private final PersonRepository personRepository;

    @Autowired
    public PersonController(final PersonRepository personRepository) {
        this.personRepository = personRepository;
    }

    @PutMapping(value = "/{person}")
    public Person savePerson(@ModelAttribute Person person) {
        return personRepository.save(person);
    }

}

但是,这不能按预期工作,因为可以通过以下失败的测试用例进行验证：

@RunWith(SpringRunner.class)
@SpringBootTest(webEnvironment = RANDOM_PORT)
public class PersonControllerTest {

    @Autowired
    private TestRestTemplate restTemplate;

    private HttpHeaders headers;

    @Before
    public void before() {
        headers = new HttpHeaders();
        headers.setContentType(APPLICATION_XML);
    }

    // Test fails
    @Test
    @DirtiesContext
    public void testSavePerson() {
        final HttpEntity<Object> request = new HttpEntity<>("<person first-name="Tin Tin" last-name="Herge" dob="1907-05-22"></person>",headers);

        final ResponseEntity<Person> response = restTemplate.exchange("/persons/1",PUT,request,Person.class,"1");
        assertThat(response.getStatusCode(),equalTo(OK));

        final Person body = response.getBody();
        assertThat(body.getFirstName(),equalTo("Tin Tin")); // Fails
        assertThat(body.getLastName(),equalTo("Herge"));
        assertThat(body.getDateOfBirth(),equalTo("1907-05-22"));
    }

}

第一个断言失败了：

java.lang.AssertionError: 
Expected: "Tin Tin"
     but: was "Tin"
Expected :Tin Tin
Actual   :Tin

换一种说法：

>不会发生服务器端异常(状态代码为200)
> Spring成功加载了id = 1的Person实例
>但其属性不会更新

有什么想法我在这里缺少什么？

注1

here提供的解决方案无效.

笔记2

提供了演示该问题的完整工作代码
here.

更多细节

预期行为：

>加载id = 1的Person实例
>使用Jaxb2RootElementHttpMessageConverter或MappingJackson2XmlHttpMessageConverter使用XML有效内容填充加载的人员实体的属性
>将其作为人员参数传递给控制器??的动作处理程序

实际行为：

>加载了id = 1的Person实例
>实例的属性未更新以匹配请求有效内容中的XML
>不会更新传递给控制器??的操作处理程序方法的person实例的属性