C/C++仿华容道小游戏
发布时间:2020-12-16 05:40:17 所属栏目:百科 来源:网络整理
导读:本文实例介绍了C++模仿华容道小游戏实现代码,供大家参考研究具体内容如下 #include stdio.h#include stdlib.h#include time.h#include stdbool.h #define maxnum 16#define colnum 4 bool numexists(int *numbers,int length,int num);int getnumbe
本文实例介绍了C++模仿华容道小游戏实现代码,分享给大家供大家参考,具体内容如下 #include <stdio.h> #include <stdlib.h> #include <time.h> #include <stdbool.h> #define maxnum 16 #define colnum 4 bool numexists(int *numbers,int length,int num); int getnumber(int **numbers,int randIndex,int *length); int* initnumbers(void); void swap(int **a,int **b); int main(int argc,char *argv[]) { int *tempnumbers = initnumbers(); int *randnumbers = initnumbers(); int **numbers; numbers = malloc(maxnum * sizeof(int*)); //bool a = numexists(numbers,16,3); //printf("a=%dn",a); int length = maxnum; srand((unsigned)time(NULL)); for (int i = 0; i < maxnum; i++) { int temp = getnumber(&tempnumbers,rand() % length,&length); randnumbers[i] = temp; numbers[temp] = &randnumbers[i]; //printf("%d%c",temp,(i + 1) % colnum == 0?'n':'t'); } if (tempnumbers != NULL) free(tempnumbers); while (true) { system("clear"); for (int i = 0; i < maxnum; i++) printf("%d%c",randnumbers[i],(i + 1) % colnum == 0?'n':'t'); printf("move number/ invalid num==exit: "); int i; if (!scanf("%d",&i)) { printf("game overn"); break; } if (i >= maxnum || i <0) { printf("sorry,i can't find %dn",i); break; } unsigned char sign = abs(numbers[i] - numbers[0]); switch (sign) { case 1: case 4: swap(&numbers[0],&numbers[i]); break; } } if (numbers != NULL) free(numbers); if (randnumbers != NULL) free(randnumbers); } void swap(int **a,int **b) { int *templocation = *a; int tempvalue = **a; **a = **b; **b = tempvalue; *a = *b; *b = templocation; } int* initnumbers(void) { int *numbers = malloc(maxnum * sizeof(int)); for (int i = 0; i < maxnum; i++) numbers[i] = i; return numbers; } int getnumber(int **numbers,int *length) { int result = (*numbers)[randIndex]; (*numbers)[randIndex] = (*numbers)[--(*length)]; int *temp = realloc(*numbers,(*length) * sizeof(int)); *numbers = temp; return result; } bool _numexists(int *numbers,int start,int end,int num) { printf("start: %d,end: %d,num: %dn",start,end,num); if (start == end) return numbers[start] == num; else { int middle = (start+end) / 2; if (numbers[middle] == num) return true; else if (numbers[middle] > num) return _numexists(numbers,middle-1,num); else return _numexists(numbers,middle+1,num); } } bool numexists(int *numbers,int num) { return _numexists(numbers,length-1,num); } 希望本文对大家学习C++程序设计有所帮助。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |
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