建立XML来发送到服务器。

发布时间：2020-12-16 05:10:30 所属栏目：百科来源：网络整理

导读：建立XML来发送到服务器。在Unity里，我没有找到可以不添加大量排行来做这个的标准函数，所以我建立了下述机制： 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 4

建立XML来发送到服务器。

在Unity里，我没有找到可以不添加大量排行来做这个的标准函数，所以我建立了下述机制：

public string buildXMLRPCRequest(Hashtable FieldArray,string MethodName)

{

string ReturnString = "" ;

ReturnString += "<?xml version="1.0" encoding="iso-8859-1"?>" +

"n" + "<simpleRPC version="0.9">" +

"n" + "<methodCall>" +

"n" + "<methodName>" + MethodName + "</methodName>" +

"n" + "<vector type="struct">" ;

ReturnString += buildNode(FieldArray);

ReturnString += "n</vector>" +

"n</methodCall>" +

"n</simpleRPC>" ;

return ReturnString;

}

public string buildNode(Hashtable FieldArray)

{

string ReturnList = "" ;

foreach (DictionaryEntry Item in FieldArray) {

string TypeName = "int" ;

string NodeType = "scalar" ;

Type myType = Item.Value.GetType();

string fieldValue = "" ;

if (myType == typeof (string) ) {

TypeName = "string" ;

fieldValue = Item.Value.ToString();

}

typeof (Hashtable) ) {

fieldValue = buildNode(Item.Value as Hashtable);

NodeType = "vector" ;

TypeName = "struct" ;

}

typeof (int) ) {

fieldValue = Item.Value.ToString();

TypeName = "int" ;

}

var ThisNode = "n<" + NodeType + " type="" + TypeName + "" id="" + Item.Key + "">" + fieldValue + "</" + NodeType + ">" ;

ReturnList += ThisNode;

}

return ReturnList;

}

buildXMLRPCRequest 是用来建立 XML的。

你想要编码的字段HashTable可能包括types: int,string 或者 Hashtable的对象。它将返回精美格式化的（简单）XML-RPC字符串，准备发送到服务器。

发送

把XML发送到服务器，你需要发出带有设置为text/xml的mine类型post请求。标准C#函数没有一个能用于Unity的，但是用这种buildXMLRPCRequest逻辑输出非常有效，它所做的是：

在Unity发送：

我使用这个代码：

private void UnityPostXML( int Staging,

string WebServer,

string MethodName,

Hashtable FieldArray)

{

string WebServiceURL = "http://LIVESERVER/" ;

if (Staging == 1) {

WebServiceURL = "http://TESTSERVER" ;

}

// Encode the text to a UTF8 byte arrray

string XMLRequest = buildXMLRPCRequest(FieldArray,MethodName);

System.Text.Encoding enc = System.Text.Encoding.UTF8;

byte[] myByteArray = enc.GetBytes(XMLRequest);

// Get the Unity WWWForm object (a post version)

var form = new WWWForm();

var url = WebServiceURL;

// Add a custom header to the request.

// Change the content type to xml and set the character set

var headers = form.headers;

headers[ "Content-Type" ]= "text/xml;charset=UTF-8" ;

// Post a request to an URL with our rawXMLData and custom headers

var www = new WWW(WebServiceURL,myByteArray,headers);

// Start a co-routine which will wait until our servers comes back

StartCoroutine(WaitForRequest(www));

}

IEnumerator WaitForRequest(WWW www)

{

yield return www;

// check for errors

if (www.error == null )

{

Debug.Log( "WWW Ok!: " + www.text);

} else {

Debug.Log( "WWW Error: " + www.error);

}

? 用UTF8把XML编码成ByteArray

? 创建一个新的Unity WWWForm

? 创建HashTable,存储当前的http标头，覆盖内容类型为text/xml。

? 发送lot给server

? 建立协程等待答复

不适用Unity发送

我发现使用C#（MonoDevelop)的标准版本）开发library比用Uinty开发一切简单多了。所以如果想用C#做同样的逻辑发送，如下：

private string NormalXMLCall(int Staging,

Hashtable Fields)

{

// Figure out who to call

string WebServiceURL = "http://LIVSERVER" ;

if (Staging == 1) {

WebServiceURL = "http://TESTSERVER" ;

}

WebServiceURL += WebServer;

// Build the request

XmlRpcParser parser = new XmlRpcParser();

string XMLRequest = parser.buildXMLRPCRequest(Fields,MethodName);

// Fire it off

HttpWebRequest httpRequest =(HttpWebRequest)WebRequest.Create(WebServiceURL);

httpRequest.Method = "POST" ;

//Defining the type of the posted data as XML

httpRequest.ContentType = "text/xml" ;

// string data = xmlDoc.InnerXml;

byte[] bytedata = Encoding.UTF8.GetBytes(XMLRequest);

// Get the request stream.

Stream requestStream = httpRequest.GetRequestStream();

// Write the data to the request stream.

requestStream.Write(bytedata,bytedata.Length);

requestStream.Close();

//Get Response

HttpWebResponse httpResponse = (HttpWebResponse)httpRequest.GetResponse();

// Get the stream associated with the response.

Stream receiveStream = httpResponse.GetResponseStream ();

// Pipes the stream to a higher level stream reader with the required encoding format.

StreamReader readStream = new StreamReader (receiveStream,Encoding.UTF8);

string ReceivedData = readStream.ReadToEnd ();

httpResponse.Close ();

readStream.Close ();

return ReceivedData;

}

从 XML中提取数据

我写了一个简单的解析器。用于下述findNode函数的构造函数应给予原始XML数据，以及你想要找到的子节点对象。如果节点可以在最高级别的XML字符串找到，它将返回该节点的值，如果找不到就null。这个解析器是特定于：简单的XML-RPC，需要花点时间来解码编码的字符，那也很简单。

public string findNode(string Xml,string SearchForTag) {

int NestCounter = 0;

bool FoundTag = false ;

int FoundTagLevel = 0;

string ReturnValue = null ;

// Break it down by "<"

string [] TagArray = Xml.Split( '<' );

for (int i=0;i<TagArray.Length;i++) {

if (i>175 && i<180) {

int Hello=1;

}

string ThisLine = "<" + TagArray[i];

if (ThisLine.Length <= 1) continue ;

if ((ThisLine.Length >= 2) && (ThisLine.Substring(0,2) == "<?" )) if ((ThisLine.Length >= 3) && (ThisLine.Substring(0,3) == "<--" )) continue ;

// It can be a vector or a scalar - vectors are full of scalars so we'll

ThisLine = ThisLine.Replace( " " , " " );

ThisLine = ThisLine.Replace( "</" , "</" );

string [] FieldArray = ThisLine.Split(' ');

bool AddLineToResult = FoundTag;

// Nest counter is the level we are operating on. We only check the first

// Level. When a vector is found we increase the NestCount and we won' t

// search for the ID

if (NestCounter <= 1) { // Initial array we are looking on level 1

（编辑：李大同）

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