8051 c中断

所以我正在做的就是向用户发送一个句子并让他们通过串口回答是或否,我使用了串行中断.那部分工作正常.如果我从那个人那里得到一个no,我想通过定时器中断产生5kHz的方波.我希望这个方波由外部中断控制,当P3.2引脚上的外部中断打开或关闭时,它会打开和关闭.
这是我的所有代码

#include <REG52.H>
#include <stdio.h>
sbit WAVE = P1 ^ 7;
#define BIT(x) (1 << (x))

void timer0() interrupt 1  // timer is controlling square wave timer 0
{
  WAVE = ~WAVE;
}

void interrupt0() interrupt 0
{
  IE ^= BIT(1);
}

void serial0() interrupt 4
{
  unsigned char x;
  unsigned int i,z;
  unsigned char yes[] = " YES ";
  unsigned char no[] = " NO ";
  unsigned char nvalid[] = " NOT VALID TRY AGAIN ";

  while (RI == 1) {

    x = SBUF;
    RI = 0;

    if (z < 1) {
      if (x == 'n') {
        for (i = 0; i < 4; i++) {
          SBUF = no[i];
          while (TI == 0) ;  //wait for transmit
          TI = 0;
          z++;
        }
      }
    } else {
      return;
    }

    if (x == 'y') {
      for (i = 0; i < 5; i++) {
        SBUF = yes[i];
        while (TI == 0) ;
        TI = 0;
      }
    } else if (x != 'n') {
      for (i = 0; i < 21; i++) {
        SBUF = nvalid[i];
        while (TI == 0) ;
        TI = 0;
      }
    }

    TI = 0;
    return;
  }
}

void main()
{
  TMOD = 0x20;
  TH1 = 0xF6;    //baud rate
  SCON = 0x50;
  TH0 = 0xA4;
  IE = 0x93;    //enable interrupts
  IP = 0x10;    // propriety to serial interrupt
  TR1 = 1;    //start timer 1
  TR0 = 1;    //clear timer 0
  TI = 1;
  printf("Hello,Are you okay? Press y for yes and n for no ");
  while (1) ;
}

我遇到问题的部分是来自前面代码的这两个中断

void timer0() interrupt 1 // timer is controlling square wave timer 0
{ 
    WAVE=~WAVE;
}

void interrupt0() interrupt 0
{
  IE ^= BIT(1);
}

任何正确方向的提示将不胜感激！谢谢.抱歉格式化