AJAX传参，JS获取当前URL参数（超级实用）

发布时间：2020-12-16 03:34:17 所属栏目：百科来源：网络整理

导读：t.html !DOCTYPE htmlhtmlheadmeta charset="UTF-8"titleInsert title here/titlescript type="text/javascript"var getParam = function(name){ var search = document.location.search; var pattern = new RegExp("[?]"+name+"=([^]+)","g"); var matcher

t.html

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>

<script type="text/javascript">

var getParam = function(name){
    var search = document.location.search;
    var pattern = new RegExp("[?&]"+name+"=([^&]+)","g");
    var matcher = pattern.exec(search);
    var items = null;
    if(null != matcher){
            try{
                    items = decodeURIComponent(decodeURIComponent(matcher[1]));
            }catch(e){
                    try{
                            items = decodeURIComponent(matcher[1]);
                    }catch(e){
                            items = matcher[1];
                    }
            }
    }
    return items;
};

window.onload=function(){
	alert(getParam('ids'));
	alert(getParam('cid'));
}
</script>
</head>
<body>

<h1>222221111</h1>


</body>
</html>

（编辑：李大同）

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