std :: make_shared< POD>()值初始化我的POD？
如果是,这是否符合标准？
如果没有(我怀疑),有没有办法呢？我猜std :: make_shared< POD>(POD())会做,但是我应该做什么？
解决方法
是的,这是值得注意的,这是由标准保证的：
§20.7.2.2.6,2:(关于make_shared)
Effects: Allocates memory suitable for an object of type T and constructs an object in that memory via the placement new expression ::new (pv) T(std::forward<Args>(args)...).
和§5.3.4,15：
A new-expression that creates an object of type T initializes that object as follows:
— If the new-initializer is omitted,the object is default-initialized (8.5); if no initialization is performed,the object has indeterminate value.
— Otherwise,the new-initializer is interpreted according to the initialization rules of 8.5 for directinitialization.
因此,它将直接初始化为新的POD().
§8.5,16：
The semantics of initializers are as follows. […]
— If the initializer is (),the object is value-initialized.
（编辑：李大同）
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