加入收藏 | 设为首页 | 会员中心 | 我要投稿 李大同 (https://www.lidatong.com.cn/)- 科技、建站、经验、云计算、5G、大数据,站长网!
当前位置: 首页 > 百科 > 正文

c – 如何从旋转角度计算OpenCV的透视变换?

发布时间:2020-12-16 03:11:17 所属栏目:百科 来源:网络整理
导读:我想从旋转角度和距离到对象的角度计算透视变换(warpPerspective函数的矩阵). 怎么做? 我在OE上找到了代码.示例程序如下: #include opencv2/objdetect/objdetect.hpp#include opencv2/highgui/highgui.hpp#include opencv2/imgproc/imgproc.hpp#include io
我想从旋转角度和距离到对象的角度计算透视变换(warpPerspective函数的矩阵).

怎么做?

我在OE上找到了代码.示例程序如下:

#include <opencv2/objdetect/objdetect.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc.hpp>

#include <iostream>
#include <math.h>

using namespace std;
using namespace cv;

Mat frame;

int alpha_int;
int dist_int;
int f_int;

double w;
double h; 
double alpha; 
double dist; 
double f;

void redraw() {

    alpha = (double)alpha_int/1000.;
    //dist = 1./(dist_int+1);
    //dist = dist_int+1;
    dist = dist_int-50;
    f = f_int+1;

    cout << "alpha = " << alpha << endl;
    cout << "dist = " << dist << endl;
    cout << "f = " << f << endl;

    // Projection 2D -> 3D matrix
    Mat A1 = (Mat_<double>(4,3) <<
        1,-w/2,1,-h/2,1);

    // Rotation matrices around the X axis
    Mat R = (Mat_<double>(4,4) <<
        1,cos(alpha),-sin(alpha),sin(alpha),1);

    // Translation matrix on the Z axis 
    Mat T = (Mat_<double>(4,dist,1);

    // Camera Intrisecs matrix 3D -> 2D
    Mat A2 = (Mat_<double>(3,4) <<
        f,w/2,f,h/2,0);

    Mat m = A2 * (T * (R * A1));

    cout << "R=" << endl << R << endl;
    cout << "A1=" << endl << A1 << endl;
    cout << "R*A1=" << endl << (R*A1) << endl;
    cout << "T=" << endl << T << endl;
    cout << "T * (R * A1)=" << endl << (T * (R * A1)) << endl;
    cout << "A2=" << endl << A2 << endl;
    cout << "A2 * (T * (R * A1))=" << endl << (A2 * (T * (R * A1))) << endl;
    cout << "m=" << endl << m << endl;

    Mat frame1;


    warpPerspective( frame,frame1,m,frame.size(),INTER_CUBIC | WARP_INVERSE_MAP);

    imshow("Frame",frame);
    imshow("Frame1",frame1);
}

void callback(int,void* ) {
    redraw();
}

void main() {


    frame = imread("FruitSample_small.png",CV_LOAD_IMAGE_COLOR);
    imshow("Frame",frame);

    w = frame.size().width;
    h = frame.size().height; 

    createTrackbar("alpha","Frame",&alpha_int,100,&callback);
    dist_int = 50;
    createTrackbar("dist",&dist_int,&callback);
    createTrackbar("f",&f_int,&callback);

    redraw();

    waitKey(-1);
}

但不幸的是,这种变化确实有些奇怪

为什么?当alpha> 0时,上面的图像的另一半是什么?以及如何围绕其他轴旋转?为什么dist这么奇怪?

解决方法

我有很多时间来思考数学和代码.我在一两年前就这样做了.我甚至在美丽的LaTeX中排版.

我有意设计了我的解决方案,使得无论提供什么旋转角度,整个输入图像被包含在输出框架内,以黑色为中心.

我的warpImage函数的参数是所有3个轴的旋转角度,比例因子和垂直视野角.该功能输出输出图像中的翘曲矩阵,输出图像和源图像的角.

数学(代码,看下面)

LaTeX源代码为here.

守则(数学,看上面)

这是一个测试应用程序,扭曲相机

#include <opencv2/core/core.hpp>
#include <opencv2/imgproc/imgproc.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <math.h>


using namespace cv;
using namespace std;


static double rad2Deg(double rad){return rad*(180/M_PI);}//Convert radians to degrees
static double deg2Rad(double deg){return deg*(M_PI/180);}//Convert degrees to radians




void warpMatrix(Size   sz,double theta,double phi,double gamma,double scale,double fovy,Mat&   M,vector<Point2f>* corners){
    double st=sin(deg2Rad(theta));
    double ct=cos(deg2Rad(theta));
    double sp=sin(deg2Rad(phi));
    double cp=cos(deg2Rad(phi));
    double sg=sin(deg2Rad(gamma));
    double cg=cos(deg2Rad(gamma));

    double halfFovy=fovy*0.5;
    double d=hypot(sz.width,sz.height);
    double sideLength=scale*d/cos(deg2Rad(halfFovy));
    double h=d/(2.0*sin(deg2Rad(halfFovy)));
    double n=h-(d/2.0);
    double f=h+(d/2.0);

    Mat F=Mat(4,4,CV_64FC1);//Allocate 4x4 transformation matrix F
    Mat Rtheta=Mat::eye(4,CV_64FC1);//Allocate 4x4 rotation matrix around Z-axis by theta degrees
    Mat Rphi=Mat::eye(4,CV_64FC1);//Allocate 4x4 rotation matrix around X-axis by phi degrees
    Mat Rgamma=Mat::eye(4,CV_64FC1);//Allocate 4x4 rotation matrix around Y-axis by gamma degrees

    Mat T=Mat::eye(4,CV_64FC1);//Allocate 4x4 translation matrix along Z-axis by -h units
    Mat P=Mat::zeros(4,CV_64FC1);//Allocate 4x4 projection matrix

    //Rtheta
    Rtheta.at<double>(0,0)=Rtheta.at<double>(1,1)=ct;
    Rtheta.at<double>(0,1)=-st;Rtheta.at<double>(1,0)=st;
    //Rphi
    Rphi.at<double>(1,1)=Rphi.at<double>(2,2)=cp;
    Rphi.at<double>(1,2)=-sp;Rphi.at<double>(2,1)=sp;
    //Rgamma
    Rgamma.at<double>(0,0)=Rgamma.at<double>(2,2)=cg;
    Rgamma.at<double>(0,2)=sg;Rgamma.at<double>(2,0)=sg;

    //T
    T.at<double>(2,3)=-h;
    //P
    P.at<double>(0,0)=P.at<double>(1,1)=1.0/tan(deg2Rad(halfFovy));
    P.at<double>(2,2)=-(f+n)/(f-n);
    P.at<double>(2,3)=-(2.0*f*n)/(f-n);
    P.at<double>(3,2)=-1.0;
    //Compose transformations
    F=P*T*Rphi*Rtheta*Rgamma;//Matrix-multiply to produce master matrix

    //Transform 4x4 points
    double ptsIn [4*3];
    double ptsOut[4*3];
    double halfW=sz.width/2,halfH=sz.height/2;

    ptsIn[0]=-halfW;ptsIn[ 1]= halfH;
    ptsIn[3]= halfW;ptsIn[ 4]= halfH;
    ptsIn[6]= halfW;ptsIn[ 7]=-halfH;
    ptsIn[9]=-halfW;ptsIn[10]=-halfH;
    ptsIn[2]=ptsIn[5]=ptsIn[8]=ptsIn[11]=0;//Set Z component to zero for all 4 components

    Mat ptsInMat(1,CV_64FC3,ptsIn);
    Mat ptsOutMat(1,ptsOut);

    perspectiveTransform(ptsInMat,ptsOutMat,F);//Transform points

    //Get 3x3 transform and warp image
    Point2f ptsInPt2f[4];
    Point2f ptsOutPt2f[4];

    for(int i=0;i<4;i++){
        Point2f ptIn (ptsIn [i*3+0],ptsIn [i*3+1]);
        Point2f ptOut(ptsOut[i*3+0],ptsOut[i*3+1]);
        ptsInPt2f[i]  = ptIn+Point2f(halfW,halfH);
        ptsOutPt2f[i] = (ptOut+Point2f(1,1))*(sideLength*0.5);
    }

    M=getPerspectiveTransform(ptsInPt2f,ptsOutPt2f);

    //Load corners vector
    if(corners){
        corners->clear();
        corners->push_back(ptsOutPt2f[0]);//Push Top Left corner
        corners->push_back(ptsOutPt2f[1]);//Push Top Right corner
        corners->push_back(ptsOutPt2f[2]);//Push Bottom Right corner
        corners->push_back(ptsOutPt2f[3]);//Push Bottom Left corner
    }
}

void warpImage(const Mat &src,double    theta,double    phi,double    gamma,double    scale,double    fovy,Mat&      dst,Mat&      M,vector<Point2f> &corners){
    double halfFovy=fovy*0.5;
    double d=hypot(src.cols,src.rows);
    double sideLength=scale*d/cos(deg2Rad(halfFovy));

    warpMatrix(src.size(),theta,phi,gamma,scale,fovy,M,&corners);//Compute warp matrix
    warpPerspective(src,dst,Size(sideLength,sideLength));//Do actual image warp
}


int main(void){
    Mat m,disp,warp;
    vector<Point2f> corners;
    VideoCapture cap(0);

    while(cap.isOpened()){
        cap >> m;
        warpImage(m,5,50,30,warp,corners);
        imshow("Disp",disp);
    }
}

(编辑:李大同)

【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容!

    推荐文章
      热点阅读