AJAX / LocalStorage：是否可以将JS变量传递给PHP？

所以一维地说,你不能将JavaScript传递给PHP.

然而…

使用Ajax,在我的情况下,我建议您使用JSON将JavaScript数据发送到PHP页面并将响应带回JavaScript方法.我认为这符合您的需求.如果你愿意,我可以提供一个简单的例子.

// – 以下示例：

JavaScript的：

//Ajax Method
function processAjax(queryString,processDiv,responseDiv) {

responseDiv.innerHTML = '';
var myAjax;
try {
    // Modern Browsers-->
    myAjax =new XMLHttpRequest();
} catch (e) {
    // antique ie browsers-->
    try {
        myAjax =new ActiveXObject("Msxml2.XMLHTTP");
    } catch (e) {
        try{
            myAjax =new ActiveXObject("Microsoft.XMLHTTP");
        } catch (e) {
            // Something went wrong
            document.getElementById('processDiv').innerHTML="";
            alert("Your browser malfunctioned!  Please try again. Consider installing a modern browser if the problem persists.");
            return false;
        }
    }
}
myAjax.onreadystatechange = function() {
    if (myAjax.readyState == 4) {
        var ajaxResponse = myAjax.responseText;
                responseDiv.innerHTML = ajaxResponse;
        processDiv.innerHTML = "";

                    //NOTE: HERE IS WHERE AJAX IS FINISHED,SO IF YOU WANT TO DO SOMETHING ELSE HERE YOU CAN!
                    //POST PROCESSING----->
                    // IE: alert('I am finished processing now!');
                    // or call another function:
                    // anotherFunction();

            } else {
        processDiv.innerHTML = '<img src="http://www.mysite.com/images/loadingicon.gif" alt="processing....." />';
    }
}
myAjax.open("GET",queryString,true);
myAjax.send(null);

}


function sendStorage() {

   var helloVar = 'Hello,I am passed to PHP #1';
   var worldVar = 'I am the second value passed to PHP!';
   var processId = 'process_div';
   var resultId = 'result_div';
   var queryString = 'http://www.mysite.com/process.php?hello=' + helloVar + '&world=' + worldVar;

   processAjax(queryString,processId,resultId);

}

现在对于一些HTML：

<div id="content">
       <div id="process_div"> This is where processing will occur </div>
       <div id="result_div"> This is where my response will display </div>
</div>

现在为process.php(注意：为安全起见,我强烈建议您不要在您的JAVASCRIPT中显示服务器端处理页面)

<?php

  //init
  $hello = '';
  $world = '';
  $errors = 0;

  //set
  //Security note: never trust a URL request.. you should clean all $_GET,$_REQUEST,AND $_POST with the PHP htmlspecialchars() method (take a look at php.net for that)
  (isset($_GET['hello'])) ? $hello = $_GET['hello'] : $errors++;
  (isset($_GET['world'])) ? $world = $_GET['world'] : $errors++;

  //process
  if($errors > 0) {
      echo 'Errors Detected! Missing querystring get data!';
  } else {
      echo '<p>Hello received: ' . $hello . '</p>';
      echo '<p>World received: ' . $world . '</p>';
      //now we can process $hello and $world server side!
  }

？>

重要提示：您应该学习一些JSON和$_POST请求,因为它们更安全,更快,您可以轻松地操作返回的数据.我建议查看像jquery这样的库来简化示例.

我没有测试过这段代码,但它应该可以工作..如果您有疑问或者这不能回答您的问题,请告诉我.

乐意效劳！