如何在不知道xml结构时用jdom解析
发布时间:2020-12-16 02:06:19 所属栏目:百科 来源:网络整理
导读:代码如下: SAXBuilder builder = new SAXBuilder(); Document doc = builder.build(new File("C:a.xml")); Element root = doc.getRootElement(); String rootName = root.getName(); //"person" List dataList = root.getChildren(); Iterator i = dataL
代码如下: SAXBuilder builder = new SAXBuilder(); Document doc = builder.build(new File("C:a.xml")); Element root = doc.getRootElement(); String rootName = root.getName(); //"person" List dataList = root.getChildren(); Iterator i = dataList.iterator(); while (i.hasNext()) { Element e = (Element) i.next(); String eKey = e.getName(); //"name","age","address" String eValue = e.getText(); //"wang","22","beijin" System.out.println("eKey==="+eKey+" ;eValue==="+eValue); } 参考地址:来自https://zhidao.baidu.com/question/49517776.html (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |