使用Ajax方法提交多个对象数组的问题

当用$.ajax()向后台提交参数时,如果参数中数组的话一般在后台会用List<T>接收;但老是不成功如下面代码

var arr1 = [{ "Name": "Tom","Age": 17 },{ "Name": "Jim","Age": 22}];
var arr2 = [{ "Name": "Tom2","Age": 18 },{ "Name": "Jim2","Age": 24}];

    $(function () {
        $.ajax({
            url: '/Home/UserAdd',data: {list1:arr1,list2:arr2},success: function (msg) {
                if (msg == '1') {
                    console.log('添加成功');
                } else {
                    console.log('添加失败');
                }
            }
        });

    })

list1[0][Name]:Tom
list1[0][Age]:17
list1[1][Name]:Jim
list1[1][Age]:22
list2[0][Name]:Tom2
list2[0][Age]:18
list2[1][Name]:Jim2
list2[1][Age]:24

C#中能识别的数组应该是这样的格式

list1[0].aa=1&list1[0].bb=2&list1[1].aa=3&list1[1].bb=4&list2[0].aa=1&list2[0].bb=2&list2[1].aa=3&list2[1].bb=4

在网上查找资料之后了解到ajax post之前会用因为jQuery需要调用jQuery.param序列化参数,我们来看下jquery源码

//在ajax()方法中，对json类型的数据进行了$.param()处理
if ( s.data && s.processData && typeof s.data !== "string" ) {
    s.data = jQuery.param( s.data,s.traditional );
}

//param方法中
if ( jQuery.isArray( a ) || ( a.jquery && !jQuery.isPlainObject( a ) ) ) {
        // Serialize the form elements
        jQuery.each( a,function() {
            add( this.name,this.value );
        });

    } else {
        // If traditional,encode the "old" way (the way 1.3.2 or older
        // did it),otherwise encode params recursively.
        for ( prefix in a ) {
            buildParams( prefix,a[ prefix ],traditional,add );
        }
    }

Array.prototype.serializeObject = function (lName) {
        var o = {};
        $t = this;
        for (var i = 0; i < $t.length; i++) {
            for (var item in $t[i]) {
                o[lName + '[' + i + '].' + item.toString()] = $t[i][item].toString();
            }
        }
        return o;
    };

$.ajax({
            url: '/Home/UserAdd',data: $.param(arr1.serializeObject("list1")) + "&" + $.param(arr2.serializeObject("list2")),success: function (msg) {
                if (msg == '1') {
                    console.log('添加成功');
                } else {
                    console.log('添加失败');
                }
            }
        });

public string UserAdd(List<User> list1,List<User> list2)
{
    return "1";
}
public class User
{
 public string Name { get; set; }
 public int Age { get; set; }
} 

这样一来问题就解决啦!

（编辑：李大同）

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