c# – WCF功能返回后继续

最简单的方法是什么？

谢谢
达摩

C#代码

//Add Files To Control Manager
    public ReturnClass FilesToControl(List<Item> lstNewItems,string ReferenceNumber,string Type,String Description)
   {
       try
       {
           String ThisisAnItemToControl = "";
           String ThisIsItsType = "";

           for (int i = 0; i < lstNewItems.Count; i++) // Loop through List with for
           {
               ThisisAnItemToControl = lstNewItems[i].Paramater;
               ThisIsItsType = lstNewItems[i].Type;

               // Do a pre check on the item

               // Does File Exist

               if (!File.Exists(ThisisAnItemToControl))
                   return new ReturnClass(-1,ThisisAnItemToControl + " does not exist",String.Empty,null,null);  



           }

           return new ReturnClass(1,"",null);


           // Now that we have returned a result to the web application we can get to work and modify the items under control but how can i do this?

         //  **??


       }

       catch (Exception ex)
       {

           return new ReturnClass(-1,ex.Message.ToString(),null);

       }