Ajax Json使用

页面

var uri=path+"/dataWrite/dataWrite_progress.action";
$.ajax({
     type: "post",url: uri,dataType: 'json',success: function (info) {
     json=eval(info);
     properess=Number(json.properess); 
     tableName=json.tableName;
     $("#message").text(tableName+"-更新进度:"+properess+"%");
     }
 });

后台

Map<String,String> message=new HashMap<String,String>();
message.put("tableName",tableName);
message.put("properess",new
java.text.DecimalFormat("#.00").format(properess));
String msg=JSONObject.fromObject(message).toString();
response.getWriter().write(msg);