c# – 将单词(字符串)转换为Int

发布时间：2020-12-16 01:21:54 所属栏目：百科来源：网络整理

导读：我确信这已经完成了一百次,但我希望有一个非常简单的方法来实现这一点.我想把单词改成int. 像下面的例子 One = 1Two = 2Three = 3 所以基本上如果我有字符串“One”它会转换为1,即使我可以返回一个字符串“1”我可以转换它. 解决方法这样做是为了好玩……可

我确信这已经完成了一百次,但我希望有一个非常简单的方法来实现这一点.我想把单词改成int.

像下面的例子

One = 1
Two = 2
Three = 3

所以基本上如果我有字符串“One”它会转换为1,即使我可以返回一个字符串“1”我可以转换它.

解决方法

这样做是为了好玩……可能有许多边缘情况会失败……

private static Dictionary<string,long> numberTable=
    new Dictionary<string,long>
        {{"zero",0},{"one",1},{"two",2},{"three",3},{"four",4},{"five",5},{"six",6},{"seven",7},{"eight",8},{"nine",9},{"ten",10},{"eleven",11},{"twelve",12},{"thirteen",13},{"fourteen",14},{"fifteen",15},{"sixteen",16},{"seventeen",17},{"eighteen",18},{"nineteen",19},{"twenty",20},{"thirty",30},{"forty",40},{"fifty",50},{"sixty",60},{"seventy",70},{"eighty",80},{"ninety",90},{"hundred",100},{"thousand",1000},{"million",1000000},{"billion",1000000000},{"trillion",1000000000000},{"quadrillion",1000000000000000},{"quintillion",1000000000000000000}};
public static long ToLong(string numberString)
{
    var numbers = Regex.Matches(numberString,@"w+").Cast<Match>()
         .Select(m => m.Value.ToLowerInvariant())
         .Where(v => numberTable.ContainsKey(v))
         .Select(v => numberTable[v]);
    long acc = 0,total = 0L;
    foreach(var n in numbers)
    {
        if(n >= 1000)
        {
            total += (acc * n);
            acc = 0;
        }
        else if(n >= 100){
            acc *= n;
        }
        else acc += n;          
    }
    return (total + acc)  * ( numberString.StartsWith("minus",StringComparison.InvariantCultureIgnoreCase) ? -1 : 1);
}

（编辑：李大同）

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