AJAX 通用与服务器段交互代码范例 客户端未传入参数-----请求ser
发布时间：2020-12-16 00:57:58 所属栏目：百科 来源：网络整理
导读：html head base href="%=basePath%" titleMy JSP 'ajax2.jsp' starting page/title meta http-equiv="pragma" content="no-cache"meta http-equiv="cache-control" content="no-cache"meta http-equiv="expires" content="0" meta http-equiv="keywords" con
<html>
<head>
<base href="<%=basePath%>">
<title>My JSP 'ajax2.jsp' starting page</title>
<meta http-equiv="pragma" content="no-cache">
<meta http-equiv="cache-control" content="no-cache">
<meta http-equiv="expires" content="0">
<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
<meta http-equiv="description" content="This is my page">
<!--
<link rel="stylesheet" type="text/css" href="styles.css">
-->
<script type="text/javascript" src="jquery-1.10.2.js"></script>
<script type="text/javascript">
$(function(){
$("#btn").click(function(){
$.ajax({
type:"POST",url:"AjaxServlet",dataType:"html",success: function(returnData){
$("#result").val(returnData);
}
});
});
});
</script>
</head>
<body>
<input type="text" id="result">
<input type="button" id="btn" value="get value from server">
</body>
</html>
package com.sun.servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class AjaxServlet extends HttpServlet {
@Override
protected void doGet(HttpServletRequest req,HttpServletResponse resp)
throws ServletException,IOException {
// TODO Auto-generated method stub
PrintWriter out = resp.getWriter();
System.out.println("do get invoked");
out.write("hello world");
out.flush();
}
@Override
protected void doPost(HttpServletRequest req,IOException {
this.doGet(req,resp);
}
}
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