原生的ajax
发布时间:2020-12-16 00:48:27 所属栏目:百科 来源:网络整理
导读:testAjax.jsp : %@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%htmlheadmeta http-equiv="Content-Type" content="text/html; charset=UTF-8"titleInsert title here/titlescript type="text/javascript"function a
testAjax.jsp : <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Insert title here</title> <script type="text/javascript"> function ajax(){ var xhr=getXhr(); xhr.onreadystatechange=function(){ if(xhr.readyState==4){ if(xhr.status==200){ document.getElementById("resText").innerHTML=xhr.responseText; } } } xhr.open('get','test',true); xhr.send(null); } function getXhr(){ var xhr=null; if(window.ActiveXObject){ xhr=new ActiveXObject("Microsoft.XMLHTTP"); }else if(window.XMLHttpRequest){ xhr=new XMLHttpRequest(); } return xhr; } </script> </head> <body> <input type="button" value="以ajax方式获取数据" onclick="ajax();"> <div id="resText"></div> </body> </html>TestServlet.java : public class TestServlet extends HttpServlet { public void doGet(HttpServletRequest request,HttpServletResponse response) throws ServletException,IOException { PrintWriter pw=response.getWriter(); pw.print("hello ajax..."); pw.close(); } }为Servlet映射的url为test。 点击按钮后: 如果get方式要传递参数,可以这样: xhr.open('get','test?name=tom&age=23',true); public class TestServlet extends HttpServlet { public void doGet(HttpServletRequest request,IOException { String name=request.getParameter("name"); String age=request.getParameter("age"); PrintWriter pw=response.getWriter(); pw.print("name:"+name+",age:"+age); pw.close(); } } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |