c# – 字段’xxx’永远不会被赋值,并且将始终具有其默认值null
发布时间:2020-12-16 00:23:44 所属栏目:百科 来源:网络整理
导读:我的错误: ???字段’StockManagement.LargeItems1.largeS’永远不会被赋值,并且将始终具有其默认值null 我的代码: namespace StockManagement{ class LargeItems1 { private Stackstring largeS; public LargeItems1() { Stackstring largeS = new Stackst
我的错误:
???字段’StockManagement.LargeItems1.largeS’永远不会被赋值,并且将始终具有其默认值null 我的代码: namespace StockManagement { class LargeItems1 { private Stack<string> largeS; public LargeItems1() { Stack<string> largeS = new Stack<string>(); } public void LargeItemsAdd() { string usersInput2,tempValue; int tempValueI = 0; bool attempt = false;//,whichOne = false; Console.WriteLine("Would you like to remove or add an item to the storage area n Reply add OR remove"); string usersInput = Console.ReadLine(); usersInput = usersInput.ToLower(); if (usersInput.Contains("remove")) { LargeItemsRemove(largeS); return; } else if (usersInput.Contains("add")) { Console.WriteLine("Please input (numerically) how many IDs you'd like to add"); tempValue = Console.ReadLine(); attempt = int.TryParse(tempValue,out tempValueI); while (!attempt) { Console.WriteLine("Please input (numerically) how many IDs you'd like to add,you did not input a numeric value last time"); tempValue = Console.ReadLine(); attempt = int.TryParse(tempValue,out tempValueI); } for (int i = 0; i < tempValueI; i++) { Console.WriteLine("Please input the ID's (one at a time) of the item you would like to add"); usersInput2 = Console.ReadLine(); if (largeS.Contains(usersInput2)) { Console.WriteLine("That ID has already been stored"); } else { largeS.Push(usersInput2); } } foreach (var item in largeS) { Console.WriteLine("Current (large) item ID's: " + item); } } } public void LargeItemsRemove(Stack<string> largeS) { if (largeS.Contains(null)) { Console.WriteLine("No IDs stored"); } else { string popped = largeS.Pop(); foreach (var item in largeS) { Console.WriteLine("Pop: " + item); } Console.WriteLine("Removed ID = " + popped); } } } } 我不明白如何将我的值分配给实例.我很感激可以提供任何帮助! 解决方法
更改构造函数以初始化字段而不是局部变量:
public LargeItems1() { this.largeS = new Stack<string>(); } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |