c# – 如何在EF中指定左连接?
发布时间:2020-12-16 00:21:26 所属栏目:百科 来源:网络整理
导读:我的模特: public partial class history_builds{ public int ID { get; set; } public int build { get; set; } public int br { get; set; } public int tag { get; set; } public string line { get; set; } public int rev { get; set; } public int us
我的模特:
public partial class history_builds { public int ID { get; set; } public int build { get; set; } public int br { get; set; } public int tag { get; set; } public string line { get; set; } public int rev { get; set; } public int user_ID { get; set; } public string distrib_path { get; set; } public string setup_path { get; set; } public System.DateTime build_date { get; set; } public string product { get; set; } } public partial class history_uploads { public int ID { get; set; } public int ID_user { get; set; } public string Line { get; set; } public int Build { get; set; } public string Distrib { get; set; } public System.DateTime Time_upload { get; set; } public int Status { get; set; } } public partial class user { public int ID { get; set; } public string Name { get; set; } public int ID_group { get; set; } } 语境: public DbSet<history_builds> history_builds { get; set; } public DbSet<history_uploads> history_uploads { get; set; } public DbSet<user> users { get; set; } 我试着做这个Entity framework left join的左连接 var items = entities.history_builds .Join( entities.users.DefaultIfEmpty(),hb => hb.user_ID,u => u.ID,(hb,u) => new { hb.distrib_path,hb.setup_path,hb.build_date,hb.build,User = (u == null ? String.Empty : u.Name),hb.rev } ) .Join(entities.history_uploads.DefaultIfEmpty(),hb => hb.build,hu => hu.Build,hu) => new HistoryBuidItem { Revision = hb.rev,Build = hb.build,DistribPath = hb.distrib_path,SetupPath = hb.setup_path,BuildDate = hb.build_date,User = hb.User,IsUpload = (hu == null ? true : false) } ) .Where(x => ids.Contains(x.Revision)) .ToList(); 但它不起作用,EF仍然发出内连接sql代码,有什么问题? 解决方法
左外连接示例:
from c in table0 join o in table1 on c.sno equals o.sno into ps from o in ps.DefaultIfEmpty() select new { c.name,o.number} 它渲染SQL: SELECT [t0].[name],[t1].[number] AS [number] FROM [table0] AS [t0] LEFT OUTER JOIN [table1] AS [t1] ON ([t0].[sno]) = [t1].[sno] (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |