C#将XML转换为字符串以便搜索它
发布时间:2020-12-16 00:18:04 所属栏目:百科 来源:网络整理
导读:我正在尝试搜索 XML文档以获取特定信息.在程序的第一部分,我将所有信息从XML显示到控制台(这很简单,我已经完成了),在第二部分,我试图在节点之间搜索特定信息,以便在控制台上显示它.我也这样做了,但我不知道如何从XML文件(order.xml)读取XML并将其转换为字符
我正在尝试搜索
XML文档以获取特定信息.在程序的第一部分,我将所有信息从XML显示到控制台(这很简单,我已经完成了),在第二部分,我试图在节点之间搜索特定信息,以便在控制台上显示它.我也这样做了,但我不知道如何从XML文件(order.xml)读取XML并将其转换为字符串以便使用它.
这是我的代码: order.xml <?xml version="1.0" encoding="utf-8" ?> <ordercat> <order order_ID="1" employee_ID="125"> <CustomerId>1</CustomerId> <OrderDate>19.12.2009</OrderDate> <ShippedDate>21.12.2011</ShippedDate> <ShipName>Sven Skanske</ShipName> <ShipAddress>Stockholm 542,Stockolm</ShipAddress> <ShipCountry>Sweden</ShipCountry> </order> <order order_ID="2" employee_ID="145"> <CustomerId>5</CustomerId> <OrderDate>25.10.2010</OrderDate> <ShippedDate>31.10.2010</ShippedDate> <ShipName>Jan Hoznovski</ShipName> <ShipAddress>Warsawska 212,Warsaw</ShipAddress> <ShipCountry>Poland</ShipCountry> </order> <order order_ID="3" customerID="4" employee_ID="112"> <CustomerId>4</CustomerId> <OrderDate>15.10.2011</OrderDate> <ShippedDate>16.10.2011</ShippedDate> <ShipName>Martin Petrzilka</ShipName> <ShipAddress>U Hrocha 2145,Sedlcany</ShipAddress> <ShipCountry>Czech Republic</ShipCountry> </order> </ordercat> 这是C#代码: using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Data; using System.Xml; using System.Xml.XPath; namespace XML { class Program { static void Main(string[] args) { DataSet ds = new DataSet(); string pathe = @"D:DocsKristianstadHomework_5XMLXMLorder.xml"; ds.ReadXml(pathe); foreach (DataTable dt in ds.Tables) { foreach (DataRow row in dt.Rows) { foreach (DataColumn column in dt.Columns) { Console.WriteLine(row[column]); } Console.WriteLine(); } } Console.WriteLine("Press any key to continue ..."); Console.ReadKey(); Console.WriteLine(""); string xmlText = "<?xml version="1.0" encoding="utf-8" ?>"; xmlText += "<ordercat>"; xmlText += "<order order_ID="1" employee_ID="125">"; xmlText += "<CustomerId>1</CustomerId>"; xmlText += "<OrderDate>19.12.2009</OrderDate>"; xmlText += "<ShippedDate>21.12.2011</ShippedDate>"; xmlText += "<ShipName>Sven Skanske</ShipName>"; xmlText += "<ShipAddress>Stockholm 542,Stockolm</ShipAddress>"; xmlText += "<ShipCountry>Sweden</ShipCountry>"; xmlText += "</order>"; xmlText += "<order order_ID="2" employee_ID="145">"; xmlText += "<CustomerId>5</CustomerId>"; xmlText += "<OrderDate>25.10.2010</OrderDate>"; xmlText += "<ShippedDate>31.10.2010</ShippedDate>"; xmlText += "<ShipName>Jan Hoznovski</ShipName>"; xmlText += "<ShipAddress>Warsawska 212,Warsaw</ShipAddress>"; xmlText += "<ShipCountry>Poland</ShipCountry>"; xmlText += "</order>"; xmlText += "<order order_ID="3" customerID="4" employee_ID="112">"; xmlText += "<CustomerId>4</CustomerId>"; xmlText += "<OrderDate>15.10.2011</OrderDate>"; xmlText += "<ShippedDate>16.10.2011</ShippedDate>"; xmlText += "<ShipName>Martin Petrzilka</ShipName>"; xmlText += "<ShipAddress>U Hrocha 2145,Sedlcany</ShipAddress>"; xmlText += "<ShipCountry>Czech Republic</ShipCountry>"; xmlText += "</order>"; xmlText += "</ordercat>"; XmlDocument xml = new XmlDocument(); xml.LoadXml(xmlText); XmlNodeList xnList = xml.SelectNodes("/ordercat/order[CustomerId='5']"); foreach (XmlNode xn in xnList) { string shippedDate = xn["ShippedDate"].InnerText; string shipName = xn["ShipName"].InnerText; Console.WriteLine(shippedDate + " " + shipName); } } } } 正如您所看到的,第一部分从XML文件中获取信息,但我必须在第二部分中使用带有XML信息的字符串.所以重复这个问题.如何在示例的第二部分使用XML文件而不是字符串?或者我如何将XML文件转换为字符串,然后在第二部分中使用它? 解决方法
怎么样
string xmlString = System.IO.File.ReadAllText(fileName); (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |