c# – 获取属性名称
发布时间:2020-12-15 23:56:31 所属栏目:百科 来源:网络整理
导读:有没有办法获取传递给函数的值的属性名称? 解决方法 你在问这是否可行? public void PrintPropertyName(int value) { Console.WriteLine(someMagicCodeThatPrintsThePropertyName);}// x is SomeClass having a property named SomeNumberPrintInteger(x =
有没有办法获取传递给函数的值的属性名称?
解决方法
你在问这是否可行?
public void PrintPropertyName(int value) { Console.WriteLine(someMagicCodeThatPrintsThePropertyName); } // x is SomeClass having a property named SomeNumber PrintInteger(x => x.SomeNumber); 和“SomeNumber”将打印到控制台? 如果是这样,不.这显然是不可能的(提示:PrintPropertyName(5)会发生什么?).但你可以这样做: public static string GetPropertyName<TSource,TProperty>(this Expression<Func<TSource,TProperty>> expression) { Contract.Requires<ArgumentNullException>(expression != null); Contract.Ensures(Contract.Result<string>() != null); PropertyInfo propertyInfo = GetPropertyInfo(expression); return propertyInfo.Name; } public static PropertyInfo GetPropertyInfo<TSource,TProperty>> expression) { Contract.Requires<ArgumentNullException>(expression != null); Contract.Ensures(Contract.Result<PropertyInfo>() != null); var memberExpression = expression.Body as MemberExpression; Guard.Against<ArgumentException>(memberExpression == null,"Expression does not represent a member expression."); var propertyInfo = memberExpression.Member as PropertyInfo; Guard.Against<ArgumentException>(propertyInfo == null,"Expression does not represent a property expression."); Type type = typeof(TSource); Guard.Against<ArgumentException>(type != propertyInfo.ReflectedType && type.IsSubclassOf(propertyInfo.ReflectedType)); return propertyInfo; } 用法: string s = GetPropertyName((SomeClass x) => x.SomeNumber); Console.WriteLine(s); 现在“SomeNumber”将打印到控制台. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |