用PHP获取Google AJAX Search API 数据的代码
发布时间:2020-12-15 23:34:48 所属栏目:百科 来源:网络整理
导读:http://code.google.com/apis/ajaxsearch/documentation/#fonje 代码如下: // This example request includes an optional API key which you will need to // remove or replace with your own key. // Read more about why it's useful to have an API key
http://code.google.com/apis/ajaxsearch/documentation/#fonje 代码如下: // This example request includes an optional API key which you will need to // remove or replace with your own key. // Read more about why it's useful to have an API key. // The request also includes the userip parameter which provides the end // user's IP address. Doing so will help distinguish this legitimate // server-side traffic from traffic which doesn't come from an end-user. $url = "http://ajax.googleapis.com/ajax/services/search/web?v=1.0&" . "q=Paris%20Hilton&key=INSERT-YOUR-KEY&userip=USERS-IP-ADDRESS"; // sendRequest // note how referer is set manually $ch = curl_init(); curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt($ch,CURLOPT_REFERER,/* Enter the URL of your site here */); $body = curl_exec($ch); curl_close($ch); // now,process the JSON string $json = json_decode($body); // now have some fun with the results... API KEY 申请地址: http://code.google.com/apis/ajaxsearch/signup.html 由此,我们可以写个函数像这样 代码如下: function google_search_api($args,$referer = '//www.52php.cn/',$endpoint = 'web'){ $url = "http://ajax.googleapis.com/ajax/services/search/".$endpoint; if ( !array_key_exists('v',$args) ) $args['v'] = '1.0'; $url .= '?'.http_build_query($args,'','&'); $ch = curl_init(); curl_setopt($ch,$referer); $body = curl_exec($ch); curl_close($ch); return json_decode($body); } // 使用示例 $rez = google_search_api(array( 'q' => '21andy.com',// 查询内容 'key' => '你申请到的API KEY', 'userip' => '你的IP地址', )); header('Content-type: text/html; charset=utf-8;'); echo ' print_r($rez); echo ' (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |