将XML文件转换为easyui Tree结构json
发布时间:2020-12-15 23:31:45 所属栏目:百科 来源:网络整理
导读:private void GetTreeCamera() { XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load(HttpContext.Current.Server.MapPath("camera.xml")); StringBuilder result = new StringBuilder(); StringBuilder sb = new StringBuilder(); //获取当前XML文档的根
private void GetTreeCamera() { XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load(HttpContext.Current.Server.MapPath("camera.xml")); StringBuilder result = new StringBuilder(); StringBuilder sb = new StringBuilder(); //获取当前XML文档的根 一级 XmlNode oNode = xmlDoc.DocumentElement; if (!oNode.HasChildNodes) result.Append("[]"); else { //获取根节点的所有子节点列表 XmlNodeList oList = oNode.ChildNodes; result.Append("["); foreach (XmlNode Node in oList) { sb.Clear(); string r1 = getJsonByNode(Node,sb); result.Append(r1); } result = result.Remove(result.Length - 1,1); result.Append("]"); } WebHelper.HttpResponseJson(result.ToString()); } /// <summary> /// 遍历结点,拼接json /// </summary> /// <param name="Node"></param> /// <param name="sb"></param> /// <returns></returns> private string getJsonByNode(XmlNode Node,StringBuilder sb) { if (!Node.HasChildNodes) { sb.Append("{"id":"" + Node.Attributes["id"].Value + "","text":"" + Node.Attributes["name"].Value.Trim() + "","state":"open"},"); } else { sb.Append("{"text":"" + Node.Attributes["name"].Value.Trim() + "","children":["); XmlNodeList oList2 = Node.ChildNodes; foreach (XmlNode Node2 in oList2) { getJsonByNode(Node2,sb); } sb = sb.Remove(sb.Length - 1,1); sb.Append("]},"); } return sb.ToString(); } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |