用JAXB从对象生成XML

发布时间：2020-12-15 23:29:59 所属栏目：百科来源：网络整理

导读：Java代码 import java.io.FileOutputStream; import javax.xml.bind.JAXBContext; import javax.xml.bind.Marshaller; import javax.xml.bind.annotation.XmlRootElement; public class JavaToXMLDemo{ static void main(String[]args) throws Exception{ JA

    Java代码 
    
  
 importjava.io.FileOutputStream;
 
importjavax.xml.bind.JAXBContext;
importjavax.xml.bind.Marshaller;
importjavax.xml.bind.annotation.XmlRootElement;
publicclassJavaToXMLDemo{
staticvoidmain(String[]args)throwsException{
 JAXBContextcontext=JAXBContext.newInstance(Employee.class);
 Marshallerm=context.createMarshaller();
 m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT,true);
 Employeeobject=newEmployee();
 object.setCode("CA");
 object.setName("Cath");
 object.setSalary(300);
 m.marshal(object,System.out);
 }
 }

@XmlRootElementclassEmployee{
privateStringcode;
privateStringname;
privateintsalary;
publicStringgetCode(){
returncode;
voidsetCode(Stringcode){
this.code=code;
publicStringgetName(){
returnname;
voidsetName(Stringname){
this.name=name;
intgetSalary(){
returnsalary;
voidsetSalary(intpopulation){
this.salary=population;
 运行结果:

    Xml代码 
    
  
<?xmlversion="1.0"encoding="UTF-8"standalone="yes"?><employee>
code>CA</name>Cathsalary>300>
（编辑：李大同）
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