c# – 如何在使用Roslyn进行编译时设置程序集版本,文化和公钥令

这样Explorer就不会在其属性页面中显示任何版本信息.资源管理器仅显示Win32 VersionInfo而不是.NET版本信息.您需要使用Rosyln发出Win32资源代码来设置这些值.幸运的是,有一种方法可以从.NET自动生成Win32信息：CreateDefaultWin32Resources.

这是一个完整且有效的代码示例：

public void VersionInfoExample()
{
    // 1. Generate AssemblyInfo.cs-like C# code and parse syntax tree
    StringBuilder asmInfo = new StringBuilder();

    asmInfo.AppendLine("using System.Reflection;");
    asmInfo.AppendLine("[assembly: AssemblyTitle("Test")]");
    asmInfo.AppendLine("[assembly: AssemblyVersion("1.1.0")]");
    asmInfo.AppendLine("[assembly: AssemblyFileVersion("1.1.0")]");
    // Product Info
    asmInfo.AppendLine("[assembly: AssemblyProduct("Foo")]");
    asmInfo.AppendLine("[assembly: AssemblyInformationalVersion("1.3.3.7")]");

    var syntaxTree = CSharpSyntaxTree.ParseText(asmInfo.ToString(),encoding: Encoding.Default);

    // 2. Create compilation
    string mscorlibPath = typeof(object).Assembly.Location;
    MetadataReference mscorlib = MetadataReference.CreateFromFile(mscorlibPath,new MetadataReferenceProperties(MetadataImageKind.Assembly));
    CSharpCompilationOptions options = new CSharpCompilationOptions(OutputKind.DynamicallyLinkedLibrary);

    CSharpCompilation compilation = CSharpCompilation.Create("Test.dll",references: new[] { mscorlib },syntaxTrees: new[] { syntaxTree },options: options);

    // 3. Emit code including win32 version info
    using (MemoryStream dllStream = new MemoryStream())
    using (MemoryStream pdbStream = new MemoryStream())
    using (Stream win32resStream = compilation.CreateDefaultWin32Resources(
                                                                versionResource: true,// Important!
                                                                noManifest: false,manifestContents: null,iconInIcoFormat: null))
    {
        EmitResult result = compilation.Emit(
                                     peStream: dllStream,pdbStream: pdbStream,win32Resources: win32resStream);

        System.IO.File.WriteAllBytes("Test.dll",dllStream.ToArray());
    }
}