c# – 生成正确的IL以使用带有通用类的新“in”修饰符的参数调用

public virtual T DoSomething(in ReadOnlySpan<byte> memory,T o);

如果我取消虚拟修改器,我运行的代码运行正常.一旦我添加虚拟修饰符,我在尝试调用生成的代码时会得到一个MethodNotFound异常.我也注意到如果我不在方法参数的任何地方使用in修饰符,它仍然可以正常工作.如果我从类中取消泛型参数(并保留in参数),则调用也适用于虚拟修饰符.它只在使用in修饰符时崩溃并且似乎使用泛型类型.

我已经将我的代码缩减为一个最小的例子,你可以在下面看到(对于代码转储很抱歉,代码中有很多我认为与整个问题相关的内容).

using System;
using System.Collections.Generic;
using System.Reflection;
using System.Reflection.Emit;
using System.Runtime.CompilerServices;
using System.Runtime.InteropServices;
using System.Text;

namespace MessageStream.Bug
{
    public class BugReproduction
    {

        public static void Main(string[] args)
        {
            var test = new TestClass<int>();
            var span = new ReadOnlySpan<byte>(new byte[] { 1 });
            test.OuterDoSomething(span,10);
        }

    }

    public class TestClass<T> where T : new()
    {

        private ITestInterface<T> testInterfaceImpl;

        public TestClass()
        {
            Initialize();
        }

        public T OuterDoSomething(in ReadOnlySpan<byte> memory,T o)
        {
            return testInterfaceImpl.DoSomething(in memory,o);
        }

        // Generates a class that implements the ITestInterface<T>.DoSomething
        // The generated class basically just calls testClass.DoSomething(in memory,o);
        private void Initialize()
        {
            Type concreteType = GetType();
            Type interfaceType = typeof(ITestInterface<T>);

            var methodToOverride = interfaceType.GetMethod(nameof(ITestInterface<T>.DoSomething));
            string overrideMethodName = string.Format("{0}.{1}",interfaceType.FullName,methodToOverride.Name);

            var typeBuilder = CreateTypeBuilderForDeserializer(GetType().Name);

            var thisField = typeBuilder.DefineField("testClass",concreteType,FieldAttributes.Private);

            var constructor = typeBuilder.DefineConstructor(
                MethodAttributes.Public | MethodAttributes.SpecialName | MethodAttributes.RTSpecialName,CallingConventions.HasThis,new[] { concreteType });

            var constructorIlGenerator = constructor.GetILGenerator();

            constructorIlGenerator.Emit(OpCodes.Ldarg_0);
            constructorIlGenerator.Emit(OpCodes.Ldarg_1);
            constructorIlGenerator.Emit(OpCodes.Stfld,thisField);
            constructorIlGenerator.Emit(OpCodes.Ret);

            var doSomethingMethodBuilder = typeBuilder.DefineMethod(
                overrideMethodName,MethodAttributes.Public | MethodAttributes.HideBySig |
                MethodAttributes.Virtual | MethodAttributes.Final,typeof(T),new Type[0],new[] 
                {
                    typeof(ReadOnlySpan<byte>).MakeByRefType(),typeof(T)
                },new[]
                {
                    new [] { typeof(InAttribute) },new Type[0]
                },new[]
                {
                    new Type[0],new Type[0]
                });

            doSomethingMethodBuilder.DefineParameter(1,ParameterAttributes.In,"memory")
                // I pulled this from a decompiled assembly. You will get a signature doesnt match exception if you don't include it.
                .SetCustomAttribute(typeof(IsReadOnlyAttribute).GetConstructors()[0],new byte[] { 01,00,00 });

            doSomethingMethodBuilder.DefineParameter(2,ParameterAttributes.None,"o");

            // Build method body
            var methodIlGenerator = doSomethingMethodBuilder.GetILGenerator();

            // Emit the call to the "DoSomething" method.
            // This fails if the virtual keyword is used on the method.
            methodIlGenerator.Emit(OpCodes.Ldarg_0);
            methodIlGenerator.Emit(OpCodes.Ldfld,thisField);
            methodIlGenerator.Emit(OpCodes.Ldarg_1);
            methodIlGenerator.Emit(OpCodes.Ldarg_2);
            methodIlGenerator.Emit(OpCodes.Callvirt,concreteType.GetMethod("DoSomething"));

            methodIlGenerator.Emit(OpCodes.Ret);

            // Point the interfaces method to the overidden one.
            typeBuilder.DefineMethodOverride(doSomethingMethodBuilder,methodToOverride);

            // Create type and create an instance
            Type objectType = typeBuilder.CreateType();
            testInterfaceImpl = (ITestInterface<T>)Activator.CreateInstance(objectType,this);
        }

        /// <summary>
        /// This will throw a MethodNotFound exception. If you remove virtual it will work though.
        /// </summary>
        public virtual T DoSomething(in ReadOnlySpan<byte> memory,T o)
        {
            Console.WriteLine(memory[0]);
            Console.WriteLine(o);

            return new T();
        }

        private static TypeBuilder CreateTypeBuilderForDeserializer(string name)
        {
            var typeSignature = $"{name}{Guid.NewGuid().ToString().Replace("-","")}";
            var an = new AssemblyName(typeSignature);
            AssemblyBuilder assemblyBuilder = AssemblyBuilder.DefineDynamicAssembly(an,AssemblyBuilderAccess.Run);
            ModuleBuilder moduleBuilder = assemblyBuilder.DefineDynamicModule($"{name}{Guid.NewGuid().ToString()}Module");
            TypeBuilder tb = moduleBuilder.DefineType(typeSignature,TypeAttributes.Public |
                    TypeAttributes.Class |
                    TypeAttributes.AutoClass |
                    TypeAttributes.AnsiClass |
                    TypeAttributes.BeforeFieldInit |
                    TypeAttributes.AutoLayout,null,new[] { typeof(ITestInterface<T>) });
            return tb;
        }

    }

    public interface ITestInterface<T>
    {

        T DoSomething(in ReadOnlySpan<byte> memory,T o);

    }

}

有任何想法吗？我一直在撞墙,试图解决这个问题几个星期了.您可以在my repository中找到实际的真实世界代码.检查benchmark project以了解正在发生的事情/如何使用它.