c# – Linq.Expression TryCatch – 将异常传递给Catch Block?
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所以我一直在修补
Linq.Expressions(如果有人可以建议一个更正确或更优雅的方式来做我正在做的事情,请随意插入)并且试图做某事时碰壁.
让我们假设我们有一个简单的数学课: public class SimpleMath {
public int AddNumbers(int number1,int number2) {
return number1 + number2;
}
}
我决定将AddNumbers方法转换为简单的Func< object,object,object>代表. 为此,我执行以下操作: // Two collections,one for Type Object paramaters and one for converting to Type int.
List<ParameterExpression> parameters = new List<ParameterExpression>();
List<Expression> convertedParameters = new List<Expression>();
// Populate collections with Parameter and conversion
ParameterExpression parameter1 = Expression.Parameter(typeof(object));
parameters.Add(parameter1);
convertedParameters.Add(Expression.Convert(parameter1,typeof(int)));
ParameterExpression parameter2 = Expression.Parameter(typeof(object));
parameters.Add(parameter2);
convertedParameters.Add(Expression.Convert(parameter2,typeof(int)));
// Create instance of SimpleMath
SimpleMath simpleMath = new SimpleMath();
// Get the MethodInfo for the AddNumbers method
MethodInfo addNumebrsMethodInfo = simpleMath.GetType().GetMethods().Where(x => x.Name == "AddNumbers").ToArray()[0];
// Create MethodCallExpression using the SimpleMath object,the MethodInfo of the method we want and the converted parameters
MethodCallExpression returnMethodWithParameters = Expression.Call(Expression.Constant(simpleMath),addNumebrsMethodInfo,convertedParameters);
// Convert the MethodCallExpression to return an Object rather than int
UnaryExpression returnMethodWithParametersAsObject = Expression.Convert(returnMethodWithParameters,typeof(object));
// Create the Func<object,object> with our converted Expression and Parameters of Type Object
Func<object,object> func = Expression.Lambda<Func<object,object>>(returnMethodWithParametersAsObject,parameters).Compile();
object result = func(20,40); // result = 60
因此,如果您运行该代码,则func应返回简单计算.但是,它接受Type对象的参数,这显然会使它在运行时遇到问题,例如: object result1 = func(20,"f"); // Throws InvalidCastException 所以我想把这个方法包装在Try … Catch中(显然,如果我们处理对AddNumbers的直接调用并将字符串作为参数传递,那么在编译时会得到这个确切的问题). 因此,为了捕获此异常,我可以执行以下操作: TryExpression tryCatchMethod = TryExpression.TryCatch(returnMethodWithParametersAsObject,Expression.Catch(typeof(InvalidCastException),Expression.Constant(55,typeof(object)))); Func<object,object>>(tryCatchMethod,parameters).Compile(); object result = func(20,"f"); // result = 55 TryExpression.TryCatch接受一个Expression主体,然后是一个CatchBlock处理程序的集合. returnMethodWithParametersAsObject是我们希望包装的表达式,Expression.Catch定义我们要捕获的Exception是Type InvalidCastException,它的Expression主体是常量,55. 因此处理异常,但除非我想在抛出异常时始终返回静态值,否则它没有多大用处.所以返回SimpleMath类我添加了一个新方法HandleException: public class SimpleMath {
public int AddNumbers(int number1,int number2) {
return number1 + number2;
}
public int HandleException() {
return 100;
}
}
按照上面的相同过程,我将新方法转换为Expression: MethodInfo handleExceptionMethodInfo = simpleMath.GetType().GetMethods().Where(x => x.Name == "HandleException").ToArray()[0]; MethodCallExpression returnMethodWithParameters2 = Expression.Call(Expression.Constant(simpleMath),handleExceptionMethodInfo); UnaryExpression returnMethodWithParametersAsObject2 = Expression.Convert(returnMethodWithParameters2,typeof(object)); 然后在创建TryCatch块时使用它: TryExpression tryCatchMethod2 = TryExpression.TryCatch(returnMethodWithParametersAsObject,returnMethodWithParametersAsObject2)); Func<object,object>>(tryCatchMethod2,"f"); // result = 100 所以这次抛出InvalidCastException时,将执行SimpleMath.HandleException方法.到目前为止一切顺利,我现在可以在出现异常时执行一些代码. 我现在的问题是,在一个正常的内联Try … Catch块中你实际上有你可以使用的异常对象.例如. try {
// Do stuff that causes an exception
} catch (InvalidCastException ex) {
// Do stuff with InvalidCastException ex
}
我可以在抛出异常时执行代码,但我似乎无法弄清楚如何实际上如同在正常的Try … Catch块中那样触及异常对象. 任何帮助,将不胜感激! 附:我知道你实际上并没有按照我上面的方式组织任何事情,但我认为有必要举例说明我想做什么的机制. 解决方法
您需要将捕获的异常作为参数传递给CatchBlock表达式.
为此你应该这样做: >更改HandleException的签名.它将以异常作为参数: public int HandleException(InvalidCastException exp)
{
// Put here some real logic. I tested it using line below
Console.WriteLine(exp.Message);
return 100;
}
>使用CatchBlock.Variable将处理的异常传递给catch块.您可以设置它使用构造函数.阅读以下代码中的评论: // Create parameter that will be passed to catch block
var excepParam = Expression.Parameter(typeof(InvalidCastException));
MethodInfo handleExceptionMethodInfo = simpleMath.GetType().GetMethods().Where(x => x.Name == "HandleException").ToArray()[0];
MethodCallExpression returnMethodWithParameters2 = Expression.Call(Expression.Constant(simpleMath),handleExceptionMethodInfo,excepParam);
UnaryExpression returnMethodWithParametersAsObject2 = Expression.Convert(returnMethodWithParameters2,typeof(object));
// Put created parameter before to CatchBlock.Variable using Expression.Catch
// that takes the first argument as ParameterExpression
TryExpression tryCatchMethod2 = TryExpression.TryCatch(returnMethodWithParametersAsObject,Expression.Catch(excepParam,returnMethodWithParametersAsObject2));
var exppp = Expression.Lambda<Func<object,parameters);
Func<object,object> func2 = Expression.Lambda<Func<object,parameters).Compile();
object result2 = func2(20,"f"); // result = 100
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