c# – Linq.Expression TryCatch – 将异常传递给Catch Block?
所以我一直在修补
Linq.Expressions(如果有人可以建议一个更正确或更优雅的方式来做我正在做的事情,请随意插入)并且试图做某事时碰壁.
让我们假设我们有一个简单的数学课: public class SimpleMath { public int AddNumbers(int number1,int number2) { return number1 + number2; } } 我决定将AddNumbers方法转换为简单的Func< object,object,object>代表. 为此,我执行以下操作: // Two collections,one for Type Object paramaters and one for converting to Type int. List<ParameterExpression> parameters = new List<ParameterExpression>(); List<Expression> convertedParameters = new List<Expression>(); // Populate collections with Parameter and conversion ParameterExpression parameter1 = Expression.Parameter(typeof(object)); parameters.Add(parameter1); convertedParameters.Add(Expression.Convert(parameter1,typeof(int))); ParameterExpression parameter2 = Expression.Parameter(typeof(object)); parameters.Add(parameter2); convertedParameters.Add(Expression.Convert(parameter2,typeof(int))); // Create instance of SimpleMath SimpleMath simpleMath = new SimpleMath(); // Get the MethodInfo for the AddNumbers method MethodInfo addNumebrsMethodInfo = simpleMath.GetType().GetMethods().Where(x => x.Name == "AddNumbers").ToArray()[0]; // Create MethodCallExpression using the SimpleMath object,the MethodInfo of the method we want and the converted parameters MethodCallExpression returnMethodWithParameters = Expression.Call(Expression.Constant(simpleMath),addNumebrsMethodInfo,convertedParameters); // Convert the MethodCallExpression to return an Object rather than int UnaryExpression returnMethodWithParametersAsObject = Expression.Convert(returnMethodWithParameters,typeof(object)); // Create the Func<object,object> with our converted Expression and Parameters of Type Object Func<object,object> func = Expression.Lambda<Func<object,object>>(returnMethodWithParametersAsObject,parameters).Compile(); object result = func(20,40); // result = 60 因此,如果您运行该代码,则func应返回简单计算.但是,它接受Type对象的参数,这显然会使它在运行时遇到问题,例如: object result1 = func(20,"f"); // Throws InvalidCastException 所以我想把这个方法包装在Try … Catch中(显然,如果我们处理对AddNumbers的直接调用并将字符串作为参数传递,那么在编译时会得到这个确切的问题). 因此,为了捕获此异常,我可以执行以下操作: TryExpression tryCatchMethod = TryExpression.TryCatch(returnMethodWithParametersAsObject,Expression.Catch(typeof(InvalidCastException),Expression.Constant(55,typeof(object)))); Func<object,object>>(tryCatchMethod,parameters).Compile(); object result = func(20,"f"); // result = 55 TryExpression.TryCatch接受一个Expression主体,然后是一个CatchBlock处理程序的集合. returnMethodWithParametersAsObject是我们希望包装的表达式,Expression.Catch定义我们要捕获的Exception是Type InvalidCastException,它的Expression主体是常量,55. 因此处理异常,但除非我想在抛出异常时始终返回静态值,否则它没有多大用处.所以返回SimpleMath类我添加了一个新方法HandleException: public class SimpleMath { public int AddNumbers(int number1,int number2) { return number1 + number2; } public int HandleException() { return 100; } } 按照上面的相同过程,我将新方法转换为Expression: MethodInfo handleExceptionMethodInfo = simpleMath.GetType().GetMethods().Where(x => x.Name == "HandleException").ToArray()[0]; MethodCallExpression returnMethodWithParameters2 = Expression.Call(Expression.Constant(simpleMath),handleExceptionMethodInfo); UnaryExpression returnMethodWithParametersAsObject2 = Expression.Convert(returnMethodWithParameters2,typeof(object)); 然后在创建TryCatch块时使用它: TryExpression tryCatchMethod2 = TryExpression.TryCatch(returnMethodWithParametersAsObject,returnMethodWithParametersAsObject2)); Func<object,object>>(tryCatchMethod2,"f"); // result = 100 所以这次抛出InvalidCastException时,将执行SimpleMath.HandleException方法.到目前为止一切顺利,我现在可以在出现异常时执行一些代码. 我现在的问题是,在一个正常的内联Try … Catch块中你实际上有你可以使用的异常对象.例如. try { // Do stuff that causes an exception } catch (InvalidCastException ex) { // Do stuff with InvalidCastException ex } 我可以在抛出异常时执行代码,但我似乎无法弄清楚如何实际上如同在正常的Try … Catch块中那样触及异常对象. 任何帮助,将不胜感激! 附:我知道你实际上并没有按照我上面的方式组织任何事情,但我认为有必要举例说明我想做什么的机制. 解决方法
您需要将捕获的异常作为参数传递给CatchBlock表达式.
为此你应该这样做: >更改HandleException的签名.它将以异常作为参数: public int HandleException(InvalidCastException exp) { // Put here some real logic. I tested it using line below Console.WriteLine(exp.Message); return 100; } >使用CatchBlock.Variable将处理的异常传递给catch块.您可以设置它使用构造函数.阅读以下代码中的评论: // Create parameter that will be passed to catch block var excepParam = Expression.Parameter(typeof(InvalidCastException)); MethodInfo handleExceptionMethodInfo = simpleMath.GetType().GetMethods().Where(x => x.Name == "HandleException").ToArray()[0]; MethodCallExpression returnMethodWithParameters2 = Expression.Call(Expression.Constant(simpleMath),handleExceptionMethodInfo,excepParam); UnaryExpression returnMethodWithParametersAsObject2 = Expression.Convert(returnMethodWithParameters2,typeof(object)); // Put created parameter before to CatchBlock.Variable using Expression.Catch // that takes the first argument as ParameterExpression TryExpression tryCatchMethod2 = TryExpression.TryCatch(returnMethodWithParametersAsObject,Expression.Catch(excepParam,returnMethodWithParametersAsObject2)); var exppp = Expression.Lambda<Func<object,parameters); Func<object,object> func2 = Expression.Lambda<Func<object,parameters).Compile(); object result2 = func2(20,"f"); // result = 100 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |