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c# – 实体框架组通过Sql生成

发布时间:2020-12-15 22:36:10 所属栏目:百科 来源:网络整理
导读:我坚持使用EF的性能问题. using (var context = new CustomDbContext()) { var result = context. TransactionLines .Where(x = x.Transaction.TransactionTypeId == 1433 (x.Transaction.Eob.EobBatchId == null || x.Transaction.Eob.EobBatch.Status == E
我坚持使用EF的性能问题.

using (var context = new CustomDbContext())
        {
            var result = context.
                TransactionLines
                .Where(x => 
                    x.Transaction.TransactionTypeId == 1433 &&
                    (x.Transaction.Eob.EobBatchId == null || x.Transaction.Eob.EobBatch.Status == EobBatchStatusEnum.Completed)
                )
                .GroupBy(x => x.VisitLine.ProcedureId)
                .Select(x => new
                {
                    Id = x.Key,PaidAmount = x.Sum(t => t.PaidAmount),Code = context.Procedures.Where(h => h.Id == x.Key).Select(h => h.Code).FirstOrDefault()
                }).ToArray();
        }

EF生成下一个sql:

SELECT 
1 AS [C1],[Project6].[ProcedureId] AS [ProcedureId],[Project6].[C2] AS [C2],[Project6].[C1] AS [C3]
FROM ( SELECT 
    [Project5].[ProcedureId] AS [ProcedureId],[Project5].[C1] AS [C1],(SELECT 
        SUM([Extent7].[PaidAmount]) AS [A1]
        FROM     [dbo].[TransactionLines] AS [Extent7]
        INNER JOIN [dbo].[Transactions] AS [Extent8] ON [Extent7].[TransactionId] = [Extent8].[Id]
        LEFT OUTER JOIN [dbo].[Eobs] AS [Extent9] ON [Extent8].[EobId] = [Extent9].[Id]
        LEFT OUTER JOIN [dbo].[EobBatches] AS [Extent10] ON [Extent9].[EobBatchId] = [Extent10].[Id]
        LEFT OUTER JOIN [dbo].[VisitLines] AS [Extent11] ON [Extent7].[VisitLineId] = [Extent11].[Id]
        WHERE (([Extent9].[EobBatchId] IS NULL) OR (1 = [Extent10].[Status])) AND ([Extent8].[TransactionTypeId] = 1433) AND (([Project5].[ProcedureId] = [Extent11].[ProcedureId]) OR (([Project5].[ProcedureId] IS NULL) AND ([Extent11].[ProcedureId] IS NULL)))) AS [C2]
    FROM ( SELECT 
        [Project4].[ProcedureId] AS [ProcedureId],[Project4].[C1] AS [C1]
        FROM ( SELECT 
            [Project2].[ProcedureId] AS [ProcedureId],(SELECT TOP (1) 
                [Extent6].[Code] AS [Code]
                FROM [dbo].[Procedures] AS [Extent6]
                WHERE [Extent6].[Id] = [Project2].[ProcedureId]) AS [C1]
            FROM ( SELECT 
                [Distinct1].[ProcedureId] AS [ProcedureId]
                FROM ( SELECT DISTINCT 
                    [Extent5].[ProcedureId] AS [ProcedureId]
                    FROM     [dbo].[TransactionLines] AS [Extent1]
                    INNER JOIN [dbo].[Transactions] AS [Extent2] ON [Extent1].[TransactionId] = [Extent2].[Id]
                    LEFT OUTER JOIN [dbo].[Eobs] AS [Extent3] ON [Extent2].[EobId] = [Extent3].[Id]
                    LEFT OUTER JOIN [dbo].[EobBatches] AS [Extent4] ON [Extent3].[EobBatchId] = [Extent4].[Id]
                    LEFT OUTER JOIN [dbo].[VisitLines] AS [Extent5] ON [Extent1].[VisitLineId] = [Extent5].[Id]
                    WHERE (([Extent3].[EobBatchId] IS NULL) OR (1 = [Extent4].[Status])) AND ([Extent2].[TransactionTypeId] = 1433)
                )  AS [Distinct1]
            )  AS [Project2]
        )  AS [Project4]
    )  AS [Project5]
)  AS [Project6]

查询持续时间约为3秒.
如果直接使用Group By编写sql查询,则查询持续时间为1.5秒,并且它使用的资源减少了一半.

SELECT sq.ProcedureId,SUM(sq.PaidAmount),(SELECT TOP(1) Procedures.Code From Procedures Where Procedures.Id = sq.ProcedureId) as Code
FROM(
    SELECT [Extent5].[ProcedureId] AS [ProcedureId],[Extent1].PaidAmount as [PaidAmount]
    FROM     [dbo].[TransactionLines] AS [Extent1]
    INNER JOIN [dbo].[Transactions] AS [Extent2] ON [Extent1].[TransactionId] = [Extent2].[Id]
    LEFT OUTER JOIN [dbo].[Eobs] AS [Extent3] ON [Extent2].[EobId] = [Extent3].[Id]
    LEFT OUTER JOIN [dbo].[EobBatches] AS [Extent4] ON [Extent3].[EobBatchId] = [Extent4].[Id]
    LEFT OUTER JOIN [dbo].[VisitLines] AS [Extent5] ON [Extent1].[VisitLineId] = [Extent5].[Id]
    WHERE (([Extent3].[EobBatchId] IS NULL) OR (1 = [Extent4].[Status])) AND ([Extent2].[TransactionTypeId] = 1433)
) sq
GROUP BY sq.ProcedureId

我写了不同的linqs但仍然无法强制EF生成GroupBy而不是子查询.
理想情况下,我不想使用函数或手动编写sql,因为我在构建linq逻辑时有很多条件.

是否有可能强制EF生成与linq中编写的SQL完全相同的SQL?

解决方法

试着避免

context.Procedures.Where(h => h.Id == x.Key).Select(h => h.Code).FirstOrDefault()

通过在GroupBy子句中包含Code – 我知道它似乎是多余的,但是已知EF在转换分组操作时遇到问题,这些操作涉及除了使用密钥访问器和聚合之外的其他内容:

//...
.GroupBy(x => new { Id = x.VisitLine.ProcedureId,x.VisitLine.Procedure.Code })
.Select(x => new
{
    Id = x.Key.Id,Code = x.Key.Code
}).ToArray();

更新:以上在我的测试环境中生成以下SQL(最新的EF6.1.3):

SELECT
    1 AS [C1],[GroupBy1].[K1] AS [ProcedureId],[GroupBy1].[A1] AS [C2],[GroupBy1].[K2] AS [Code]
    FROM ( SELECT
        [Extent5].[ProcedureId] AS [K1],[Extent6].[Code] AS [K2],SUM([Filter1].[PaidAmount]) AS [A1]
        FROM    (SELECT [Extent1].[VisitLineId] AS [VisitLineId],[Extent1].[PaidAmount] AS [PaidAmount]
            FROM    [dbo].[TransactionLine] AS [Extent1]
            INNER JOIN [dbo].[Transaction] AS [Extent2] ON [Extent1].[TransactionId] = [Extent2].[Id]
            LEFT OUTER JOIN [dbo].[Eob] AS [Extent3] ON [Extent2].[EobId] = [Extent3].[Id]
            LEFT OUTER JOIN [dbo].[EobBatch] AS [Extent4] ON [Extent3].[EobBatchId] = [Extent4].[Id]
            WHERE (1433 = [Extent2].[TransactionTypeId]) AND ([Extent3].[EobBatchId] IS NULL OR [Extent4].[Status] = 1) ) AS [Filter1]
        LEFT OUTER JOIN [dbo].[VisitLine] AS [Extent5] ON [Filter1].[VisitLineId] = [Extent5].[Id]
        LEFT OUTER JOIN [dbo].[Procedure] AS [Extent6] ON [Extent5].[ProcedureId] = [Extent6].[Id]
        GROUP BY [Extent5].[ProcedureId],[Extent6].[Code]
    )  AS [GroupBy1]

这比我预想的要好得多.

更新2:EF是一个奇怪的野兽.使用双投影可产生所需的结果:

//...
.GroupBy(x => x.VisitLine.ProcedureId)
.Select(x => new
{
    Id = x.Key,})
.Select(x => new
{
    x.Id,x.PaidAmount,Code = context.Procedures.Where(h => h.Id == x.Id).Select(h => h.Code).FirstOrDefault()
}).ToArray();

产生以下内容:

SELECT
    1 AS [C1],[Project2].[ProcedureId] AS [ProcedureId],[Project2].[C1] AS [C2],[Project2].[C2] AS [C3]
    FROM ( SELECT
        [GroupBy1].[A1] AS [C1],(SELECT TOP (1)
            [Extent6].[Code] AS [Code]
            FROM [dbo].[Procedure] AS [Extent6]
            WHERE [Extent6].[Id] = [GroupBy1].[K1]) AS [C2]
        FROM ( SELECT
            [Extent5].[ProcedureId] AS [K1],SUM([Filter1].[PaidAmount]) AS [A1]
            FROM   (SELECT [Extent1].[VisitLineId] AS [VisitLineId],[Extent1].[PaidAmount] AS [PaidAmount]
                FROM    [dbo].[TransactionLine] AS [Extent1]
                INNER JOIN [dbo].[Transaction] AS [Extent2] ON [Extent1].[TransactionId] = [Extent2].[Id]
                LEFT OUTER JOIN [dbo].[Eob] AS [Extent3] ON [Extent2].[EobId] = [Extent3].[Id]
                LEFT OUTER JOIN [dbo].[EobBatch] AS [Extent4] ON [Extent3].[EobBatchId] = [Extent4].[Id]
                WHERE (1433 = [Extent2].[TransactionTypeId]) AND ([Extent3].[EobBatchId] IS NULL OR [Extent4].[Status] = 1) ) AS [Filter1]
            LEFT OUTER JOIN [dbo].[VisitLine] AS [Extent5] ON [Filter1].[VisitLineId] = [Extent5].[Id]
            GROUP BY [Extent5].[ProcedureId]
        )  AS [GroupBy1]
    )  AS [Project2]

附:如果不清楚,请回答您的具体问题

Is it possible to force EF to generate SQL exactly as it was written within linq ?

没有.相反,您应该以某种方式编写LINQ查询,以获得所需(或更接近)的SQL查询.

(编辑:李大同)

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