基础Ajax发送请求
发布时间:2020-12-15 21:06:37 所属栏目:百科 来源:网络整理
导读:function goAjax(para){var xmlHttp = null;var time = new Date();var flash = time.getTime();try{// Firefox,Opera 8.0+,Safari,IE7xmlHttp = new XMLHttpRequest();}catch (e){// Old IEtry{xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");}catch (e
function goAjax(para) { var xmlHttp = null; var time = new Date(); var flash = time.getTime(); try {// Firefox,Opera 8.0+,Safari,IE7 xmlHttp = new XMLHttpRequest(); } catch (e) {// Old IE try { xmlHttp = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) { alert("Your browser does not support XMLHTTP!"); return; } } xmlHttp.open("Get","<%=path%>/test.action?para=" + para + "&flash=" + flash,false); xmlHttp.send(null); var returnData = xmlHttp.responseText; return returnData; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |