c# – 如何将单个整数值列拆分为n列?
发布时间:2020-12-15 19:28:52 所属栏目:百科 来源:网络整理
导读:我有一个SQL Server表table_name,如: col1 123456789...N 我想要如下输出 col-1 | col-2 | col-3 | col-4 |col-5-------------------------------1 | 2 | 3 | 4 |56 | 7 | 8 | 9 |1011 | 12 | 13 | 14 |15 如何从sql-server查询中获取此输出. 解决方法 另一
我有一个SQL Server表table_name,如:
col1 1 2 3 4 5 6 7 8 9 . . . N 我想要如下输出 col-1 | col-2 | col-3 | col-4 |col-5 ------------------------------- 1 | 2 | 3 | 4 |5 6 | 7 | 8 | 9 |10 11 | 12 | 13 | 14 |15 如何从sql-server查询中获取此输出. 解决方法
另一种选择是Dynamic Pivot.
这将创建N列. 例 Declare @nCols int = 5 Declare @SQL varchar(max) = ' Declare @nCols int = '+str(@nCols,5)+' Select * From ( Select RowNr = ((row_number() over (order by col1)-1)/@nCols)+1,ColNr = concat(''col-'',isnull(nullif((row_number() over (order by col1))%@nCols,0),@nCols)),Value = col1 From YourTable ) A Pivot (max(Value) For ColNr in (' + Stuff((Select Top (@nCols) ','+QuoteName(concat('col-',Row_Number() Over (Order By (Select NULL)))) From YourTable For XML Path('')),1,'') + ') ) p' Exec(@SQL); --Print @SQL 返回 如果@nCols = 3,结果为:
这个版本你可以提供 >列数@NbrCols(与上面相同) Declare @NbrCols int = 5 Declare @FromSrc varchar(max) = 'YourTable' -- Or SQL '(Select col ...)' Declare @ColName varchar(100) = 'col1' Declare @ColPrfx varchar(100) = 'Col-' Declare @SQL varchar(max) = ' Declare @NbrCols int = '+str(@NbrCols,5)+' Select * From ( Select Row = ((row_number() over (order by '+quotename(@ColName)+')-1)/@NbrCols)+1,Col = concat('''+@ColPrfx+''',isnull(nullif((row_number() over (order by '+quotename(@ColName)+'))%@NbrCols,@NbrCols)),Val = '+quotename(@ColName)+' From '+@FromSrc+' A1 ) A Pivot (max(Val) For Col in (' + Stuff((Select Top (@NbrCols) ','+QuoteName(concat(@ColPrfx,Row_Number() Over (Order By (Select NULL)))) From master..spt_values For XML Path('')),'') + ') ) p' Exec(@SQL); --Print @SQL (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |