c# – 使用Expression创建带嵌套类的谓词

发布时间：2020-12-15 18:08:13 所属栏目：百科来源：网络整理

导读：我有这个： public class Company{ public int Id { get; set; } public string Name { get; set; }}public class City{ public int Id { get; set; } public string Name { get; set; } public int ZipCode { get; set; }}public class Person{ public int

我有这个：

public class Company
{
    public int Id { get; set; }
    public string Name { get; set; }
}
public class City
{
    public int Id { get; set; }
    public string Name { get; set; }
    public int ZipCode { get; set; }
}
public class Person
{
    public int Id { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public int? Age { get; set; }
    public City City { get; set; }
    public Company Company { get; set; }
}

我想在某种情况下生成这样的谓词：

var result = listPerson.Where(x => x.Age == 10).ToList<>();

或这个：

var result  = listPerson.Where( x => x.Company.Name == 1234).ToList();

或这个：

var result  = listPerson.Where( x => x.City.ZipCode == "MyZipCode").ToList();

或这个：

var result  = listPerson.Where( x => x.Company.Name == "MyCompanyName").ToList();

然后我创建了一个“PredicateBuilder”,这是我的工作(我得到类型,如果可以为空,我构建谓词)当我这样做时：

BuildPredicate<Person>("Age",10); I get this : x => x.Age == 10

但是当我有这样的嵌套属性时,我不会如何管理：

BuildPredicate<Person>("City.ZipCode","MyZipCode"); 
I'd like get this : x => x.City.ZipCode == "MyZipCode"

或这个：

BuildPredicate<Person>("City.Name","MyName"); 
I'd like get this : x => x.City.Name == "MyName"

或这个：

BuildPredicate<Person>("Company.Name","MyCompanyName"); 
I'd like get this : x => x.Company.Name == "MyCompanyName"

解决方法

(不打算复制Jon – OP联系我提供答案)

以下似乎工作正常：

static Expression<Func<T,bool>> BuildPredicate<T>(string member,object value) {
    var p = Expression.Parameter(typeof(T));
    Expression body = p;
    foreach (var subMember in member.Split('.')) {
        body = Expression.PropertyOrField(body,subMember);
    }
    return Expression.Lambda<Func<T,bool>>(Expression.Equal(
        body,Expression.Constant(value,body.Type)),p);
}

这和Jon的答案之间唯一的区别在于它通过告诉Expression.Constant预期的类型是什么来稍微处理null.作为使用示范：

static void Main() {
    var pred = BuildPredicate<Person>("City.Name","MyCity");

    var people = new[] {
        new Person { City = new City { Name = "Somewhere Else"} },new Person { City = new City { Name = "MyCity"} },};
    var person = people.AsQueryable().Single(pred);
}

（编辑：李大同）

【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容!