c# – 为什么不调用我的基类的静态构造函数？

发布时间：2020-12-15 18:03:42 所属栏目：百科来源：网络整理

导读：参见英文答案 What’s the best way to ensure a base class’s static constructor is called?6个可以说我有两节课： public abstract class Foo{ static Foo() { print("4"); }}public class Bar : Foo{ static Bar() { print("2"); } static void DoSome

参见英文答案 > What’s the best way to ensure a base class’s static constructor is called?6个
可以说我有两节课：

public abstract class Foo
{
    static Foo()
    {
        print("4");
    }
}

public class Bar : Foo
{
    static Bar()
    {
        print("2");
    }

    static void DoSomething()
    {
        /*...*/
    }
}

我预计在调用Bar.DoSomething()之后(假设这是我第一次访问Bar类),事件的顺序将是：

> Foo的静态构造函数(再次,假设首次访问)>打印4
> Bar的静态构造函数>打印2
>执行DoSomething

在底线我预计会打印42张.
经过测试,似乎只有2个正在打印.
And that is not even an answer.

你能解释一下这种行为吗？

解决方法

规范说明：

The static constructor for a class executes at most once in a given application domain. The execution of a static constructor is triggered by the first of the following events to occur within an application domain:

An instance of the class is created.

Any of the static members of the class are referenced.

因为您没有引用基类的任何成员,所以构造函数不会被驱逐.

试试这个：

public abstract class Foo
{
    static Foo()
    {
        Console.Write("4");
    }

    protected internal static void Baz()
    {
        // I don't do anything but am called in inherited classes' 
        // constructors to call the Foo constructor
    }
}

public class Bar : Foo
{
    static Bar()
    {
        Foo.Baz();
        Console.Write("2");
    }

    public static void DoSomething()
    {
        /*...*/
    }
}

欲获得更多信息：

> C# in Depth – Jon Skeet: C# and beforefieldinit
> StackOverflow: What’s the best way to ensure a base class’s static constructor is called?

（编辑：李大同）

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