我应该采用哪种C#模板方法？

将模板更改为此格式您好{Name.First}

现在创建一个JavaScriptSerializer来转换字典中的JSON< string,object>

JavaScriptSerializer jss = new JavaScriptSerializer();
dynamic d = jss.Deserialize(data,typeof(object));

现在变量d在字典中具有JSON的值.

有了这个,您可以针对正则表达式运行模板,以递归方式将{X.Y.Z.N}替换为字典的键.

完整示例：

public void Test()
{
    // Your template is simpler
    string template = "Hi {Name.First}";

    // some JSON
    string data = @"{""Name"":{""First"":""Jack"",""Last"":""Smith""}}";

    JavaScriptSerializer jss = new JavaScriptSerializer();

    // now `d` contains all the values you need,in a dictionary
    dynamic d = jss.Deserialize(data,typeof(object));

    // running your template against a regex to
    // extract the tokens that need to be replaced
    var result = Regex.Replace(template,@"{?{([^}]+)}?}",(m) =>
        {
            // Skip escape values (ex: {{escaped value}} )
            if (m.Value.StartsWith("{{"))
                return m.Value;

            // split the token by `.` to run against the dictionary
            var pieces = m.Groups[1].Value.Split('.');
            dynamic value = d;

            // go after all the pieces,recursively going inside
            // ex: "Name.First"

            // Step 1 (value = value["Name"])
            //    value = new Dictionary<string,object>
            //    {
            //        { "First": "Jack" },{ "Last": "Smith" }
            //    };

            // Step 2 (value = value["First"])
            //    value = "Jack"

            foreach (var piece in pieces)
            {
                value = value[piece]; // go inside each time
            }

            return value;
        });
}

我没有处理异常(例如找不到值),你可以处理这种情况并返回匹配的值(如果找不到). m.Value表示原始值或m.Groups [1].{}之间的字符串值.