C#解析Lrc歌词文件过程详解
看到很多人解析歌词文件时写了一大片的字符处理代码,而且看得不是很明白,所以自己研究了一下, 标准格式: public class Lrc { /// <summary> /// 歌曲 /// </summary> public string Title { get; set; } /// <summary> /// 艺术家 /// </summary> public string Artist { get; set; } /// <summary> /// 专辑 /// </summary> public string Album { get; set; } /// <summary> /// 歌词作者 /// </summary> public string LrcBy { get; set; } /// <summary> /// 偏移量 /// </summary> public string Offset { get; set; } /// <summary> /// 歌词 /// </summary> public Dictionary<double,string> LrcWord = new Dictionary<double,string>(); /// <summary> /// 获得歌词信息 /// </summary> /// <param name="LrcPath">歌词路径</param> /// <returns>返回歌词信息(Lrc实例)</returns> public static Lrc InitLrc(string LrcPath) { Lrc lrc = new Lrc(); using (FileStream fs = new FileStream(LrcPath,FileMode.Open,FileAccess.Read,FileShare.Read)) { string line; using (StreamReader sr = new StreamReader(fs,Encoding.Default)) { while ((line = sr.ReadLine()) != null) { if (line.StartsWith("[ti:")) { lrc.Title = SplitInfo(line); } else if (line.StartsWith("[ar:")) { lrc.Artist = SplitInfo(line); } else if (line.StartsWith("[al:")) { lrc.Album = SplitInfo(line); } else if (line.StartsWith("[by:")) { lrc.LrcBy = SplitInfo(line); } else if (line.StartsWith("[offset:")) { lrc.Offset = SplitInfo(line); } else { Regex regex = new Regex(@"[([0-9.:]*)]+(.*)",RegexOptions.Compiled); MatchCollection mc = regex.Matches(line); double time = TimeSpan.Parse("00:" + mc[0].Groups[1].Value).TotalSeconds; string word = mc[0].Groups[2].Value; lrc.LrcWord.Add(time,word); } } } } return lrc; } /// <summary> /// 处理信息(私有方法) /// </summary> /// <param name="line"></param> /// <returns>返回基础信息</returns> static string SplitInfo(string line) { return line.Substring(line.IndexOf(":") + 1).TrimEnd(']'); } } 一行代码:Lrc lrc= Lrc.InitLrc("test.lrc"); 我将分离好的歌词放入了Dictionary<double,string>里,当然也可以直接用数组存,格式就要看实际的用途了,把这些都交给TimeSpan来做吧。 很久以前有人提出了这个问题:一行歌词里面有多个时间会报错,这么久了也没见人把好的方案提供出来,今天我花了点时间,修改了下,下面是获取歌词方法
/// <summary> /// 获得歌词信息 /// </summary> /// <param name="LrcPath">歌词路径</param> /// <returns>返回歌词信息(Lrc实例)</returns> public static Lrc InitLrc(string LrcPath) { Lrc lrc = new Lrc(); Dictionary<double,string> dicword = new Dictionary<double,string>(); using (FileStream fs = new FileStream(LrcPath,Encoding.Default)) { while ((line = sr.ReadLine()) != null) { if (line.StartsWith("[ti:")) { lrc.Title = SplitInfo(line); } else if (line.StartsWith("[ar:")) { lrc.Artist = SplitInfo(line); } else if (line.StartsWith("[al:")) { lrc.Album = SplitInfo(line); } else if (line.StartsWith("[by:")) { lrc.LrcBy = SplitInfo(line); } else if (line.StartsWith("[offset:")) { lrc.Offset = SplitInfo(line); } else { try { Regex regexword = new Regex(@".*](.*)"); Match mcw = regexword.Match(line); string word = mcw.Groups[1].Value; Regex regextime = new Regex(@"[([0-9.:]*)]",RegexOptions.Compiled); MatchCollection mct = regextime.Matches(line); foreach (Match item in mct) { double time = TimeSpan.Parse("00:" + item.Groups[1].Value).TotalSeconds; dicword.Add(time,word); } } catch { continue; } } } } } lrc.LrcWord = dicword.OrderBy(t => t.Key).ToDictionary(t => t.Key,p => p.Value); return lrc; } 以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持编程小技巧。 (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |