c# – 为“半月刊”添加多少天

发布时间：2020-12-15 04:30:02 所属栏目：百科来源：网络整理

导读：我有一个名为PaymentFrequency的枚举类型,其值表示每年有多少付款… 所以我有 public enum PaymentFrequency{ None = 0,Annually = 1,SemiAnnually = 2,EveryFourthMonth = 3,Quarterly = 4,BiMonthly = 6,Monthly = 12,EveryFourthWeek = 13,SemiMonthly =

我有一个名为PaymentFrequency的枚举类型,其值表示每年有多少付款…
所以我有

public enum PaymentFrequency
{
    None             = 0,Annually         = 1,SemiAnnually     = 2,EveryFourthMonth = 3,Quarterly        = 4,BiMonthly        = 6,Monthly          = 12,EveryFourthWeek  = 13,SemiMonthly      = 24,BiWeekly         = 26,Weekly           = 52
}

基于NumberOfPayments,PaymentFrequency和FirstPaymentDate(类型为DateTimeOffset),我想计算LastPaymentDate.但是我有一个问题是在SemiMonthly的情况下确定要添加多少时间单位(天,月)……

switch (paymentFrequency)
    {
        // add years...
        case PaymentFrequency.Annually:
            LastPaymentDate = FirstPaymentDate.AddYears(NumberOfPayments - 1); 
            break;
        // add months...
        case PaymentFrequency.SemiAnnually:
            LastPaymentDate = FirstPaymentDate.AddMonths((NumberOfPayments - 1) * 6); // 6 months
            break;
        case PaymentFrequency.EveryFourthMonth:
            LastPaymentDate = FirstPaymentDate.AddMonths((NumberOfPayments - 1) * 4); // 4 months
            break;
        case PaymentFrequency.Quarterly:
            LastPaymentDate = FirstPaymentDate.AddMonths((NumberOfPayments - 1) * 3); // 3 months
            break;
        case PaymentFrequency.BiMonthly:
            LastPaymentDate = FirstPaymentDate.AddMonths((NumberOfPayments - 1) * 2); // 2 months
            break;
        case PaymentFrequency.Monthly:
            LastPaymentDate = FirstPaymentDate.AddMonths(NumberOfPayments - 1);
            break;
        // add days...
        case PaymentFrequency.EveryFourthWeek:
            LastPaymentDate = FirstPaymentDate.AddDays((NumberOfPayments - 1) * 4 * 7); // 4 weeks (1 week = 7 days)
            break;
        case PaymentFrequency.SemiMonthly:
            // NOTE: how many days in semi month? AddMonths (0.5) does not work :)
            LastPaymentDate = FirstPaymentDate.AddMonths((NumberOfPayments - 1) * 0.5); // 2 weeks (1 week = 7 days)
            break;
        case PaymentFrequency.BiWeekly:
            LastPaymentDate = FirstPaymentDate.AddDays((NumberOfPayments - 1) * 2 * 7); // 2 weeks (1 week = 7 days)
            break;
        case PaymentFrequency.Weekly:
            LastPaymentDate = FirstPaymentDate.AddDays((NumberOfPayments - 1) * 7); // 1 week (1 week = 7 days)
            break;
        case PaymentFrequency.None:
        default:
            throw new ArgumentException("Payment frequency is not initialized to valid value!","paymentFrequency");
    }

那么,使用SemiMonthly时我应该使用多少天/月？
如果不知道每个月的确切天数,这是否可能？
或者这真的很简单,我刚用完了咖啡因而且我没有看到森林里的树木:)

解决方法

对于半月刊,如果您的第一笔付款始终是该月的第一笔付款(即,从第1日到第13日的任何时间,从第13日开始,如评论中所讨论的那样有问题),您可以执行以下操作：

// assuming first payment will be 1st of month,add month for every 2 payments
 // num payments / 2 (int division,remainder is chucked)
 // then add 15 days if this is even payment of the month
 LastPaymentDate = FirstPaymentDate.AddMonths((NumberOfPayments - 1) / 2)
     .AddDays((NumberOfPayments % 2) == 0 ? 15 : 0);

因此,对于第一次付款,这将添加0个月和0天,因此是第一个付款日期.对于第二次付款,这将增加0个月(int dividision,其余被清除)和15个月的16个月.对于第三次付款,这将增加1个月(1/3)和下个月1日的0天等.

这假设FirstPaymentDate将在某个月的第一天.如果你想让第16个成为开始日期等,你可能会看到从这里去的地方等.

合理？

所以说明一下,如果我们有：

DateTime LastPaymentDate,FirstPaymentDate = new DateTime(2011,12,5);

for(int numOfPayments=1; numOfPayments<=24; numOfPayments++)
{
    LastPaymentDate = FirstPaymentDate.AddMonths((numOfPayments - 1) / 2)
        .AddDays((numOfPayments % 2) == 0 ? 15 : 0);

    Console.WriteLine(LastPaymentDate);
}

这个循环会给我们：

12/5/2011 12:00:00 AM
12/20/2011 12:00:00 AM
1/5/2012 12:00:00 AM
// etc...
10/20/2012 12:00:00 AM
11/5/2012 12:00:00 AM
11/20/2012 12:00:00 AM

（编辑：李大同）

【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容!