objective-c – Xcode：如何在图像触摸时更改图像(相同位置)？

发布时间：2020-12-15 01:42:54 所属栏目：百科来源：网络整理

导读：简单地说,我已经在UIView中使用Interface Builder放置了一个图像.现在我想在触摸该图像时运行方法/功能,例如当应该加载另一个图像时. 我的代码： - (void)touchesended:(NSSet*) touches withEvent:(UIEvent *)event { // UITouch *touch = [touch anyObject

简单地说,我已经在UIView中使用Interface Builder放置了一个图像.现在我想在触摸该图像时运行方法/功能,例如当应该加载另一个图像时.

我的代码：

- (void)touchesended:(NSSet*) touches withEvent:(UIEvent *)event 
{
    // UITouch *touch = [touch anyObject];
    bild_1_1.image = [UIImage imageNamed:@"t_1_4.jpg"];
}

解决方法

您需要处理来自UIView的触摸事件.要做到这一点,你应该创建UIView的子类并添加你的touchesBegan：withEvent：方法的实现,这里最简单的例子：

//  TouchSimpleView.h
@interface TouchSimpleView : UIImageView {
    id  delegate;
}
@property(retain) id delegate;
@end

@interface NSObject(TouchSimpleView)
-(void)didTouchView:(UIView *)aView;
@end 

//  TouchSimpleView.m
#import "TouchSimpleView.h"
@implementation TouchSimpleView
@synthesize delegate;
- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event {
    NSLog(@"touchesBegan!!! ");
    if ( delegate != nil && [delegate respondsToSelector:@selector(didTouchView:)] ) {
        [delegate didTouchView:self];
    } 
    [super touchesBegan:touches withEvent:event];
}
@end

然后,当您想要处理触摸时,可以使用此类的视图,例如：

- (void)applicationDidFinishLaunching:(UIApplication *)application {    
    [window makeKeyAndVisible];
    touchView = [[TouchSimpleView alloc] initWithFrame:CGRectMake(50,50,200,300)];
    touchView.delegate = self;
    [window addSubview:touchView];

    imageView =[[UIImageView alloc] initWithFrame:touchView.frame];
    imageView.image = [UIImage imageNamed:@"image1.png"];
    [touchView addSubview:imageView];
}

-(void)didTouchView:(UIView *)aView{
    NSLog(@"view touched,changing image");
    imageView.image = [UIImage imageNamed:@"image2.png"];
}

（编辑：李大同）

【声明】本站内容均来自网络，其相关言论仅代表作者个人观点，不代表本站立场。若无意侵犯到您的权利，请及时与联系站长删除相关内容!