cocos2d html5 互相推挤的精灵
发布时间:2020-12-14 19:16:25 所属栏目:百科 来源:网络整理
导读:update:function () { if(1) { for (var j = 0; j this._paddles.length; j++) { var _obj1 = this._paddles[j]; if (!_obj1) break; for (var i = j+1; i this._paddles.length; i++) { var _obj2 = this._paddles[i]; if (!_obj2) break; var _lenth = thi
update:function () { if(1) { for (var j = 0; j < this._paddles.length; j++) { var _obj1 = this._paddles[j]; if (!_obj1) break; for (var i = j+1; i < this._paddles.length; i++) { var _obj2 = this._paddles[i]; if (!_obj2) break; var _lenth = this.calculateLenth(_obj1.getPosition(),_obj2.getPosition()); var _minLenth = 40*2; if(_minLenth>_lenth) { var _centerPoint = cc.p((_obj1.x + _obj2.x)/2,(_obj1.y + _obj2.y)/2); var _moveLenth = (_lenth - _minLenth) /2; var _randian = this.calculateRadian(_obj1.getPosition(),_obj2.getPosition()); cc.log(_randian); var _offset = cc.p(Math.sin(_randian)*_moveLenth,Math.cos(_randian)*_moveLenth); _obj1.runAction( cc.moveBy(0.1,cc.p(_offset.x,_offset.y))); _obj2.runAction( cc.moveBy(0.1,cc.p(-_offset.x,-_offset.y))); } } } } },calculateLenth:function(p1,p2) { var _offsetX = p1.x - p2.x; var _offsetY = p1.y - p2.y; var _lenth = Math.sqrt(_offsetX*_offsetX + _offsetY*_offsetY); return _lenth; },calculateRadian:function(p1,p2) { var _offsetX = p1.x - p2.x; var _offsetY = p1.y - p2.y; var _radian = Math.atan(_offsetX/ _offsetY); if(p1.y > p2.y) { _radian +=Math.PI; } return _radian; } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |