xcode – Swift-设置可见菜单控制器

发布时间：2020-12-14 18:58:17 所属栏目：百科来源：网络整理

导读：我正在尝试显示UimenuController,但我无法查看它.我能怎么做？ let MenuController: UIMenuController = UIMenuController.sharedMenuController() MenuController.menuVisible = true MenuController.arrowDirection = UIMenuControllerArrowDirection.Down

我正在尝试显示UimenuController,但我无法查看它.我能怎么做？

let MenuController: UIMenuController = UIMenuController.sharedMenuController()
 MenuController.menuVisible = true
 MenuController.arrowDirection = UIMenuControllerArrowDirection.Down
 MenuController.setTargetRect(CGRectMake(100,80,50,50),inView: self.view)
 let MenuItem_1: UIMenuItem = UIMenuItem(title: "Menu",action: "delete:")
 let MenuItems: NSArray = [delete]
 MenuController.menuItems = MenuItems

解决方法

为了实际显示菜单,您需要执行以下操作：

>在获得sharedMenuController之前调用becomeFirstResponder()
>最后调用menu.setMenuVisible(true,animated：true)
>覆盖canBecomeFirstResponder函数
>覆盖canPerformAction函数
>为选择器编写功能

这是一个例子

func someFunc() {
    becomeFirstResponder()
    var menu = UIMenuController.sharedMenuController()
    var deleteItem = UIMenuItem(title: "Delete me",action: Selector("deleteLine"))
    menu.menuItems = [deleteItem]
    menu.setTargetRect(CGRectMake(100,inView: self)
    menu.setMenuVisible(true,animated: true)
}

func deleteLine() {
    //Do something here
}

override func canBecomeFirstResponder() -> Bool {
    return true
}

override func canPerformAction(action: Selector,withSender sender: AnyObject?) -> Bool {
    // You need to only return true for the actions you want,otherwise you get the whole range of
    //  iOS actions. You can see this by just removing the if statement here.
    if action == Selector("deleteLine") {
        return true
    }
    return false
}

（编辑：李大同）

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