ios – Xcode UI测试允许系统警报系列
发布时间:2020-12-14 18:09:41 所属栏目:百科 来源:网络整理
导读:我有问题,如果我尝试允许系列系统警报,只工作一次,下一个警报不“允许” 我在Google上搜索更多时间,并了解该帖子:( Xcode 7 UI Testing: how to dismiss a series of system alerts in code) 没什么..不行. 这是我当前的代码,首先警告“允许”成功,未检测到
我有问题,如果我尝试允许系列系统警报,只工作一次,下一个警报不“允许”
我在Google上搜索更多时间,并了解该帖子:( Xcode 7 UI Testing: how to dismiss a series of system alerts in code) 没什么..不行. 这是我当前的代码,首先警告“允许”成功,未检测到下一个警报.. XCUIApplication *app = [[XCUIApplication alloc] init]; app.launchEnvironment = @{ @"isUITest" : @YES,@"withFakeData" : fakeData }; [app launch]; for (int i = 1; i <= self.possibleSystemAlerts; i++) { NSLog(@"%d",i); XCTestExpectation *expectation = [self expectationWithDescription:@"High Expectations"]; id monitor = [self addUIInterruptionMonitorWithDescription:@"Push notifications" handler:^BOOL(XCUIElement *_Nonnull interruptingElement) { XCUIElement *element = interruptingElement; XCUIElement *allow = element.buttons[@"Allow"]; XCUIElement *ok = element.buttons[@"OK"]; if ([ok exists]) { [ok tap]; [expectation fulfill]; return YES; } if ([allow exists]) { [allow forceTap]; [expectation fulfill]; return YES; } return NO; }]; [app tap]; [self waitForExpectationsWithTimeout:6.0 handler:^(NSError *error) { if (error) { NSLog(@"Timeout Error: %@",error); } }]; [self removeUIInterruptionMonitor:monitor]; } 最好的祝福, UPD: 好的,我找到了解决方案,如何在第一次提醒后,尝试关闭第二个(感谢这个网站:http://www.it1me.com/it-answers?id=32148965&s=Template:Viper&ttl=Xcode+7+UI+Testing%3A+how+to+dismiss+a+series+of+system+alerts+in+code)只需要返回总是没有. 但另一个问题…… t = 10.18s Find: Descendants matching type Alert t = 10.18s Find: Identity Binding t = 11.19s Find the "Allow “MyApp” to access your location while you use the app?" Alert (retry 1) t = 11.19s Snapshot accessibility hierarchy for com.apple.springboard t = 11.26s Find: Descendants matching type Alert t = 11.26s Find: Identity Binding t = 12.27s Find the "Allow “MyApp” to access your location while you use the app?" Alert (retry 2) t = 12.27s Snapshot accessibility hierarchy for com.apple.springboard t = 12.33s Find: Descendants matching type Alert t = 12.34s Find: Identity Binding t = 12.42s Assertion Failure: UI Testing Failure - No matches found for "Allow “MyApp” to access your location while you use the app?" Alert Query input was {( Alert 0x7febe8731630: traits: 72057602627862528,{{25.0,193.0},{270.0,182.0}},label: '“MyApp” Would Like to Send You Notifications' )} 他尝试关闭第三个通知,而不是第二个,当然他没有找到这个系统警报…… 解决方法
在应用启动之前逐个创建警报处理程序.此外,在与警报交互之前,请务必在应用上的任意位置点按().这是Xcode中的已知错误.
addUIInterruptionMonitor(withDescription:"First Dialog") { (alert) -> Bool in alert.buttons["Allow"].tap() return true } addUIInterruptionMonitor(withDescription:"Second Dialog") { (alert) -> Bool in alert.buttons["Allow"].tap() return true } addUIInterruptionMonitor(withDescription:"Third Dialog") { (alert) -> Bool in alert.buttons["Allow"].tap() return true } let app = XCUIApplication() app.launch() app.tap() app.tap() app.tap() 这三个水龙头将连续启动每个警报处理程序,而不会实际触发您的应用程序中的任何事件.另请注意,每个中断处理程序都不会指定有关警报的任何内容,只会指定确认按钮. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |