iphone：在UIWebView中弹出按钮

您引用的弹出窗口称为UIMenuController.您可以访问[UIMenuController sharedMenuController]方法来获取菜单控制器.然后,您可以将自己的UIMenuItem添加到菜单控制器.

UIMenuItem* myBtn1 = [[[UIMenuItem alloc] initWithTitle: @"Button 1" action:@selector( onButton1: )] autorelease];
UIMenuItem* myBtn2 = [[[UIMenuItem alloc] initWithTitle: @"Button 2" action:@selector( onButton2: )] autorelease];
UIMenuController* mc = [UIMenuController sharedMenuController];
mc.menuItems = [NSArray arrayWithObjects: myBtn1,myBtn2,nil];

现在实现这些方法

- (void) onButton1: (UIMenuController*) sender
{
}

- (void) onButton2: (UIMenuController*) sender
{
}

有关详细信息,请参阅apple’s Doc.

编辑

你可以实现Long Gesture

UILongPressGestureRecognizer* gr = [[[UILongPressGestureRecognizer alloc] initWithTarget: self action: @selector( onShowMenu: ) ] autorelease];
   [_myview addGestureRecognizer: gr];



- (void) onShowMenu: (UIGestureRecognizer*) sender
{
    [sender.view becomeFirstResponder];

    UIMenuController* mc = [UIMenuController sharedMenuController];

    CGRect bounds = sender.view.bounds;

    [mc setTargetRect: sender.view.frame inView: sender.view.superview];
    [mc setMenuVisible: YES animated: YES];
}