ios – 如何在Swift / Xcode中对1个数组进行排序,并通过相同的键

var names = [ "Paul","John","David" ]
var ages  = [  35,42,27 ]

let newOrder = names.enumerate().sort({$0.1<$1.1}).map({$0.0})

names = newOrder.map({names[$0]})
ages  = newOrder.map({ages[$0]})

[编辑]以下是对该技术的改进：

这是相同的方法,但只需一步完成排序和分配.
(可以重新分配给原始数组或单独的数组)

(firstNames,ages,cities,countries,actives) = 
    {( 
       $0.map{firstNames[$0]},$0.map{ages[$0]},$0.map{cities[$0]},$0.map{countries[$0]},$0.map{actives[$0]} 
    )} 
    (firstNames.enumerated().sorted{$0.1<$1.1}.map{$0.0})

[EDIT2]和一个数组扩展,以便在您进行排序时更容易使用：

extension Array where Element:Comparable
{
   func ordering(by order:(Element,Element)->Bool) -> [Int]
   { return self.enumerated().sorted{order($0.1,$1.1)}.map{$0.0} }
}

extension Array 
{
   func reorder<T>(_ otherArray:inout [T]) -> [Element] 
   {
      otherArray = self.map{otherArray[$0 as! Int]}
      return self
   }
}


firstNames.ordering(by: <)
          .reorder(&firstNames)
          .reorder(&ages)
          .reorder(&cities)
          .reorder(&countries)
          .reorder(&actives)

结合前两个：

extension Array
{
   func reordered<T>(_ otherArray:[T]) -> [T] 
   {
      return self.map{otherArray[$0 as! Int]}
   }
}

(firstNames,actives) = 
    {( 
       $0.reordered(firstNames),$0.reordered(ages),$0.reordered(cities),$0.reordered(countries),$0.reordered(actives) 
    )} 
    (firstNames.ordering(by:<))