正则表达式 – 为什么`stoutest`不是有效的正则表达式？

发布时间：2020-12-14 06:22:10 所属栏目：百科来源：网络整理

导读：从 perlop 开始： If “/” is the delimiter then the initial m is optional. With the m you can use any pair of non-whitespace characters as delimiters. This is particularly useful for matching path names that contain “/”,to avoid LTS (lea

从 perlop开始：

If “/” is the delimiter then the initial m is optional. With the m you can use any pair of non-whitespace characters as delimiters. This is particularly useful for matching path names that contain “/”,to avoid LTS (leaning toothpick syndrome). If “?” is the delimiter,then the match-only-once rule of ?PATTERN? applies. If “‘” is the delimiter,no interpolation is performed on the PATTERN. When using a character valid in an identifier,whitespace is required after the m.

所以我可以把任何一封信作为分隔符.最终这个正则表达式应该没问题：

stoutest

那可以改写

s/ou/es/

但它似乎在Perl中不起作用.为什么？

$perl -e '$_ = qw/ou/; stoutest; print'
ou

因为Perl无法挑选出操作符

perldoc perlop说这个

Any non-whitespace delimiter may replace the slashes. Add space after the s when using a character allowed in identifiers.

这个程序工作正常

my $s = 'bout';
$s =~ s toutest;
say $s;

产量

best

（编辑：李大同）

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