Swift：Popover解雇回调

发布时间：2020-12-14 05:49:05 所属栏目：百科来源：网络整理

导读：我的Storyboard中有两个UIViewConrollers：MainViewController和SecondViewController.当用户点击名为Show Popover的按钮时,我将把SecondViewController显示为弹出框： //MainViewControlleroverride func prepareForSegue(segue: UIStoryboardSegue,sender:

我的Storyboard中有两个UIViewConrollers：MainViewController和SecondViewController.当用户点击名为Show Popover的按钮时,我将把SecondViewController显示为弹出框：

//MainViewController
override func prepareForSegue(segue: UIStoryboardSegue,sender: AnyObject?)
{

    if segue.identifier == "GoToSecondViewControllerSegue"
    {
        var vc = segue.destinationViewController as! SecondViewController
        var controller = vc.popoverPresentationController

        if controller != nil
        {
            controller?.delegate = self
            vc.inputTextDelegate = "I'm a popover!"
        }
    }
}

func popoverPresentationControllerDidDismissPopover(popoverPresentationController: UIPopoverPresentationController) {
     println("done")
}

func adaptivePresentationStyleForPresentationController(controller: UIPresentationController) -> UIModalPresentationStyle
{
    return .None
}

//SecondViewController
@IBAction func dismissPopover(sender: UIButton) {
     dismissViewControllerAnimated(true,completion: nil)
     //This dismisses the popover but does not notify the MainViewConroller
}

segue的锚点连接到一个按钮：

现在我有两个问题：

>当我点击popover内的取消按钮时,它会解除弹出窗口但不会在MainViewController中触发popoverPresentationControllerDidDismissPopover
>我如何将数据从SecondViewController传递到MainViewController,例如UITextView的文本值.

或者,更简单地说,当您手动关闭弹出窗口时,只需手动调用iOS的委托方法.

dismissViewControllerAnimated(true,completion: nil)
    popoverPresentationController?.delegate?.popoverPresentationControllerDidDismissPopover?(popoverPresentationController!)

（编辑：李大同）

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