swift – 使用dataTask返回值的函数
发布时间:2020-12-14 05:47:30 所属栏目:百科 来源:网络整理
导读:我不想检查我的url statusCode是否等于200,如果statusCode等于200,我创建了一个返回布尔函数的函数,我正在使用dataTask,但我不知道如何返回一个值: class func checkUrl(urlString: String) - Bool{ let urlPath: String = urlString var url: NSURL = NSUR
我不想检查我的url statusCode是否等于200,如果statusCode等于200,我创建了一个返回布尔函数的函数,我正在使用dataTask,但我不知道如何返回一个值:
class func checkUrl(urlString: String) -> Bool{ let urlPath: String = urlString var url: NSURL = NSURL(string: urlPath)! var request: NSURLRequest = NSURLRequest(url: url as URL) var response: URLResponse? let session = Foundation.URLSession.shared var task = session.dataTask(with: request as URLRequest,completionHandler: {(data,response,error) in if let error = error { print(error) } if let data = data{ print("data =(data)") } if let response = response { print("url = (response.url!)") print("response = (response)") let httpResponse = response as! HTTPURLResponse print("response code = (httpResponse.statusCode)") if httpResponse.statusCode == 200{ return true } else { return false } } }) task.resume() } if else中的返回值返回错误:
为了返回值,你应该使用块.尝试声明你的功能如下:
class func checkUrl(urlString: String,finished: ((isSuccess: Bool)->Void) { let urlPath: String = urlString var url: NSURL = NSURL(string: urlPath)! var request: NSURLRequest = NSURLRequest(url: url as URL) var response: URLResponse? let session = Foundation.URLSession.shared var task = session.dataTask(with: request as URLRequest,error) in if let error = error { print(error) } if let data = data{ print("data =(data)") } if let response = response { print("url = (response.url!)") print("response = (response)") let httpResponse = response as! HTTPURLResponse print("response code = (httpResponse.statusCode)") if httpResponse.statusCode == 200{ finished(isSuccess: true) } else { finished(isSuccess: false) } } }) task.resume() } 然后像这样调用它: checkUrl("http://myBestURL.com",finished { isSuccess in // Handle logic after return here }) 希望这会有所帮助. (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |