Swift(iOS 8 SDK)将Unmanaged转换为ABMultiValueRef

发布时间：2020-12-14 05:42:01 所属栏目：百科来源：网络整理

导读：我需要从AddressBook框架转换此函数的返回值： ABRecordCopyValue(nil,kABPersonPhoneProperty) 值为ABMultiValueRef类型此功能当前标记为： func ABRecordCopyValue(record: ABRecordRef!,property: ABPropertyID) - UnmanagedAnyObject! 所以我可以把它转

我需要从AddressBook框架转换此函数的返回值：

ABRecordCopyValue(nil,kABPersonPhoneProperty)

值为ABMultiValueRef类型

此功能当前标记为：

func ABRecordCopyValue(record: ABRecordRef!,property: ABPropertyID) -> Unmanaged<AnyObject>!

所以我可以把它转换为非管理像这样：

ABRecordCopyValue(person,kABPersonPhoneProperty) as Unmanaged<ABMultiValueRef>

但是如何才能将其作为ABMultiValueRef获取,以便我可以将其传递给此函数？

func ABMultiValueGetIndexForIdentifier(multiValue: ABMultiValueRef!,identifier: ABMultiValueIdentifier) -> CFIndex

我做到了

let managedPhones = Unmanaged.fromOpaque(phones.toOpaque()).takeUnretainedValue() as ABMultiValueRef

我不断得到这个编译器错误：

Bitcast requires both operands to be pointer or neither
%89 = bitcast %objc_object* %88 to %PSs9AnyObject_,!dbg !325
LLVM ERROR: Broken function found,compilation aborted!
Command /Applications/Xcode6-Beta3.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/swift failed with exit code 1

我找到了解决方案：

func peoplePickerNavigationController(
  peoplePicker: ABPeoplePickerNavigationController!,didSelectPerson person: ABRecordRef!) {

    /* Do we know which picker this is? */
    if peoplePicker != personPicker{
      return
    }

    /* Get all the phone numbers this user has */
    let unmanagedPhones = ABRecordCopyValue(person,kABPersonPhoneProperty)
    let phones: ABMultiValueRef =
    Unmanaged.fromOpaque(unmanagedPhones.toOpaque()).takeUnretainedValue()
      as NSObject as ABMultiValueRef

    let countOfPhones = ABMultiValueGetCount(phones)

    for index in 0..<countOfPhones{
      let unmanagedPhone = ABMultiValueCopyValueAtIndex(phones,index)
      let phone: String = Unmanaged.fromOpaque(
        unmanagedPhone.toOpaque()).takeUnretainedValue() as NSObject as String

      println(phone)
    }  
}

（编辑：李大同）

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