如何快速获取Ip地址
发布时间:2020-12-14 05:41:42 所属栏目:百科 来源:网络整理
导读:我如何获取我的本地IpAddress? 我试图使用这个Obj C的例子:how to get ip address of iphone programatically 当我得到函数getifaddrs()我不能得到任何进一步.我不能使用这个功能. 有没有办法做到这一点,或者我接近这个错误的方式? 原来在讨论中,OP需要Ma
我如何获取我的本地IpAddress?
我试图使用这个Obj C的例子:how to get ip address of iphone programatically 当我得到函数getifaddrs()我不能得到任何进一步.我不能使用这个功能. 有没有办法做到这一点,或者我接近这个错误的方式?
原来在讨论中,OP需要Mac上的界面地址,而不是像我以前想的那样在iOS设备上.问题中引用的代码检查
接口名称“en0”,这是iPhone上的WiFi接口.在Mac上,它使得更多 意思是检查任何“正在运行”界面. 所以我改写了答案.现在是Swift的代码翻译 Detect any connected network. getifaddrs()定义在< ifaddrs.h>中,默认情况下不包括. #include <ifaddrs.h> 以下函数返回 func getIFAddresses() -> [String] { var addresses = [String]() // Get list of all interfaces on the local machine: var ifaddr : UnsafeMutablePointer<ifaddrs> = nil if getifaddrs(&ifaddr) == 0 { // For each interface ... var ptr = ifaddr while ptr != nil { defer { ptr = ptr.memory.ifa_next } let flags = Int32(ptr.memory.ifa_flags) var addr = ptr.memory.ifa_addr.memory // Check for running IPv4,IPv6 interfaces. Skip the loopback interface. if (flags & (IFF_UP|IFF_RUNNING|IFF_LOOPBACK)) == (IFF_UP|IFF_RUNNING) { if addr.sa_family == UInt8(AF_INET) || addr.sa_family == UInt8(AF_INET6) { // Convert interface address to a human readable string: var hostname = [CChar](count: Int(NI_MAXHOST),repeatedValue: 0) if (getnameinfo(&addr,socklen_t(addr.sa_len),&hostname,socklen_t(hostname.count),nil,socklen_t(0),NI_NUMERICHOST) == 0) { if let address = String.fromCString(hostname) { addresses.append(address) } } } } } freeifaddrs(ifaddr) } return addresses } Swift 3的更新:除了采用代码 func getIFAddresses() -> [String] { var addresses = [String]() // Get list of all interfaces on the local machine: var ifaddr : UnsafeMutablePointer<ifaddrs>? guard getifaddrs(&ifaddr) == 0 else { return [] } guard let firstAddr = ifaddr else { return [] } // For each interface ... for ptr in sequence(first: firstAddr,next: { $0.pointee.ifa_next }) { let flags = Int32(ptr.pointee.ifa_flags) var addr = ptr.pointee.ifa_addr.pointee // Check for running IPv4,IPv6 interfaces. Skip the loopback interface. if (flags & (IFF_UP|IFF_RUNNING|IFF_LOOPBACK)) == (IFF_UP|IFF_RUNNING) { if addr.sa_family == UInt8(AF_INET) || addr.sa_family == UInt8(AF_INET6) { // Convert interface address to a human readable string: var hostname = [CChar](repeating: 0,count: Int(NI_MAXHOST)) if (getnameinfo(&addr,NI_NUMERICHOST) == 0) { let address = String(cString: hostname) addresses.append(address) } } } } freeifaddrs(ifaddr) return addresses } (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |