正则表达式 – R列表字符删除
发布时间:2020-12-14 05:57:09 所属栏目:百科 来源:网络整理
导读:lst1是一个列表: lst1 - list(c("all the apples","apples in the tables","fashion prosthetics"),c("meteorological concepts","effects of climate change","environmental")) 我想保留列表结构并从所有单词中删除最后一个.所需答案如下: lst1[[1]][1]
lst1是一个列表:
lst1 <- list(c("all the apples","apples in the tables","fashion prosthetics"),c("meteorological concepts","effects of climate change","environmental")) 我想保留列表结构并从所有单词中删除最后一个.所需答案如下: > lst1 [[1]] [1] "all the apple" "apple in the table" "nature" [[2]] [1] "meteorological concept" "effect of climate change" [3] "environmental" 我试过了 gsub("'s|s$|s[[:space:]]{0}","",lst1) 但它不保留列表结构. 怎么做到呢? 解决方法
您可以使用带有lapply的gsub循环遍历列表元素
lapply(lst1,gsub,pattern= "'s|s$|sb",replacement='') #[[1]] #[1] "all the apple" "apple in the table" "fashion prosthetic" #[[2]] #[1] "meteorological concept" "effect of climate change" #[3] "environmental" (编辑:李大同) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |